제출 #1260318

#제출 시각아이디문제언어결과실행 시간메모리
1260318anteknneGraph (BOI20_graph)C++20
0 / 100
2 ms2624 KiB
#include<bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;

#define pb push_back
#define pii pair<int, int>
#define pll pair<ll, ll>
#define st first
#define nd second
#define ordered_set tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update>
#define debug false

const int MAXN = 100 * 1000 + 17;
const int INF = 100 * 1000 * 1000;
vector<pii> graf[MAXN];
int c[MAXN];
int C[MAXN];
bool odw[MAXN];
bool ODW[MAXN];
vector<int> vec;
vector<int> kand = {1000 * 1000, 500 * 1000, 0, -1000 * 1000, -500 * 1000, 2000 * 1000, -2000 * 1000};
int n;

void DFS (int v) {
    vec.pb(v);
    for (auto x : graf[v]) {
        if (!odw[x.st]) {
            odw[x.st] = true;
            c[x.st] = x.nd - c[v];
            DFS(x.st);
        }
    }
}

bool licz (int v, int x) {
    vec.clear();

    c[v] = x;
    odw[v] = true;
    DFS(v);

    for (int i = 1; i <= n; i ++) {
        for (auto x : graf[i]) {
            if (c[i] + c[x.st] != x.nd) {
                return false;
            }
        }
    }

    return true;
}

int main () {
    ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    int m;
    cin >> n >> m;

    int a, b, r;
    for (int i = 0; i < m; i ++) {
        cin >> a >> b >> r;
        if (a == b) {
            r *= 2;
        }
        graf[a].pb({b, r * 1000 * 1000});
        graf[b].pb({a, r * 1000 * 1000});
    }

    int cnt = 0;
    for (int i = 1; i <= n; i ++) {
        c[i] = INF;
    }
    for (int v = 1; v <= n; v ++) {
        if (int(graf[v].size()) == 0) {
            ODW[v] = true;
            cnt ++;
            C[v] = 0;
            continue;
        }
        if (ODW[v]) {
            continue;
        }
        for (auto i : kand) {
            if (ODW[v]) {
                break;
            }

            if (licz(v, i)) {
                for (auto x : vec) {
                    ODW[x] = true;
                    C[x] = c[x];
                    cnt ++;
                }
            }
            for (auto x : vec) {
                c[x] = INF;
                odw[x] = false;
            }

        }
    }

    if (cnt == n) {
        cout << "TAK\n";
        for (int i = 1; i <= n; i ++) {
            cout << ld(C[i])/ld(1000 * 1000) << " ";
        }
        cout << "\n";
    } else {
        cout << "NIE\n";
    }



    return 0;
}


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