제출 #1259500

#제출 시각아이디문제언어결과실행 시간메모리
1259500yf_yusufPalembang Bridges (APIO15_bridge)C++20
22 / 100
117 ms15920 KiB
//```// YF YUSUF #define YF ios_base::sync_with_stdio(0);cout.setf(ios::fixed); #define YUSUF cout.precision(0);cout.tie(0);cin.tie(0); #include <bits/stdc++.h> // #include <iostream> // #include <vector> // #include <set> // #include <map> // #include <algorithm> // #include <unordered_map> // #include <cmath> // #include <numeric> // #include <queue> // #include <stack> // #include <cassert> // #include <climits> // #include <string> // #include <cstdlib> using namespace std; #ifdef YF_CHECK bool Output=1; // #include "g/debug.h" // #include "g/bigint.h" // #include "g/text.h" #else #pragma GCC optimize ("unroll-loops") #pragma GCC optimize ("inline") #pragma GCC optimize ("Ofast") #pragma GCC optimize ("O3") bool Output=0; #define deb(x...) 42 #endif #ifdef DEV bool LOUT=1; #else bool LOUT=0; #endif using ll = long long; using ld = long double; using sll = set <ll>; using vll = vector <ll>; using mll = map <ll,ll>; using pll = pair <ll,ll>; using vvl = vector <vll>; using vpll = vector <pll>; template<class T>T MIN(T&a,T b){a=min(a,b);return a;} template<class T>T MAX(T&a,T b){a=max(a,b);return a;} #define revers(a) reverse(all(a)) #define all(a) a.begin(),a.end() #define sortt(a) sort(all(a)) #define sgr v+v+1,(tl+tr)/2+1,tr #define sgl v+v,tl,(tl+tr)/2 #define pb push_back #define ins insert #define S second #define F first ll BP(ll a,ll b,ll mod=1e9+7){ if(b==0)return 1; ll q=BP(a,b/2,mod); return ((q*q)%mod*(b%2?a:1ll))%mod; } ll f(ll x){return x*(x+1)/2;} ll dup(ll a,ll b){return (a+b-1)/b;} ll lcm(ll a,ll b){return a/__gcd(a,b)*b;} ll invf(ll x){return (-1+sqrt(1+8*x))/2;} ll log(ll x){return 63 - __builtin_clzll(x);} const ll mod=998244353; const ll INF=1e18; const ll inf=1e9+7; const ll N =1e6+7; ll n,k; void YF_MAIN(ll TEST){ cin>>k>>n; ll sum = 0, add = 10 * n * inf; vpll V; vll L, R, pl, pr; L = R = pl = pr = {0}; set<ll>st; for(int i=1;i<=n;i++){ char a,b; ll v,u; cin>>a>>v>>b>>u; st.ins(v); st.ins(u); sum+=abs(v - u); if(a==b)continue; sum++; if(v>u)swap(v, u); V.pb({v, u}); L.pb(v); R.pb(u); } sortt(L); // for(auto i : L)cout<<i<<" "; // cout<<"\n"; sortt(R); ll m = L.size()-1; for(int i=1;i<=m;i++){ pl.pb(L[i] + pl.back()); pr.pb(R[i] + pr.back()); } for(auto pos : st){ ll now = 0; { ll l=0,r=m,j=0; while(l<=r){ ll m = (l+r)/2; if(R[m] < pos){ j = m; l = m+1; } else{ r=m-1; } } now += pos*j - pr[j]; } { ll l=1,r=m,j=m+1; while(l<=r){ ll m = (l+r)/2; if(L[m] > pos){ j = m; r=m-1; } else{ l = m+1; } } // cout<<pl.back()<<" "<<pl[j-1]<<" "<<j<<"\n"; now += (pl.back() - pl[j-1]) - pos*(m-j+1); } // cout<<pos<<" "<<now<<"\n"; MIN(add, now); } // cout<<sum<<" "<<add*2; cout<<sum + add*2; } bool TECT=0; bool CASE=0; bool OUTP=1; const ll LN=1e1 + 7; ll lg[LN]; const ll SN=2e1 + 7; ll SM[SN]; const ll FN=2e1 + 7; ll FACT[FN],inv[FN],FMOD=inf; ll PER(ll n,ll k){return FACT[n] *inv[n-k]%FMOD;} ll CNK(ll n,ll k){return PER(n,k)*inv[k ]%FMOD;} void BEFORE(){ for(ll i=2;i<SN;i++){ if(SM[i])continue; for(ll j=i;j<SN;j+=i) MAX(SM[j],i); } for(int i=2;i<LN;i++) lg[i]=lg[i/2]+1; FACT[0]=inv[0]=1; for(int i=1;i<FN;i++){ FACT[i]=FACT[i-1]*i%FMOD; if(i<5e5+7)inv[i]=BP(FACT[i],FMOD-2,FMOD); } } signed main(){ if(OUTP){YF YUSUF} // freopen((".in"),"r",stdin);freopen((".out"),"w",stdout); cout<<(LOUT && Output ? "\nYF_OUTPUT:\n\n" : ""); int TEST=1; if(TECT) cin>>TEST; BEFORE(); for(int T=1;T<=TEST;T++){ if(CASE) cout<<"Case "<<T<<": "; YF_MAIN(T); cout<<(T==TEST ? "" : "\n"); } return 0; } //```
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