Submission #1258860

#	Time	Username	Problem	Language	Result	Execution time	Memory
1258860		Sam_arvandi	Skyscraper (JOI16_skyscraper)	C++20	5 / 100	10 ms	9544 KiB

skyscraper

#include <bits/stdc++.h>
using namespace std;

typedef long long ll;
typedef pair<ll, ll> pii;

#define FOR(i, j, n) for(ll i = j; i<= n; i++)
#define ROF(i, n, j) for(ll i = n; i>= j; i--)
#define pb push_back
#define F first
#define S second
#define IOS ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0)
#define G(i, j) get<j-1>(i)
#define prll(x) cout << #x << ": " << x << endl;

const ll mn = 8 + 5, mn2 = (1<<8) + 5, ml = 1000 + 5, mod = 1e9 + 7;
ll dp[mn2][mn][ml], a[mn], two[mn];

inline ll ghadr(ll x, ll y)
{
        return max(x, y)-min(x, y);
}

signed main()
{
        IOS;
        ll n, L;
        cin >> n >> L;
        two[0] = 1;
        FOR(i, 1, n)
        {
                two[i] = two[i-1]*2;
        }
        FOR(i, 1, n) cin >> a[i];
        vector<ll> tmp;
        FOR(mask, 1, (1<<n)-1)
        {
                tmp.clear();
                ll t = 0;
                FOR(j, 0, n-1)
                {
                        if ((mask&two[j]))
                        {
                                t++;
                                tmp.pb(j+1);
                        }
                }
                if (t == 1)
                {
                        ll i = tmp[0];
                        FOR(j, 0, L)
                        {
                                dp[mask][i][j] = 1;
                        }
                        continue;
                }
                for(auto i: tmp)
                {
                        FOR(x, 0, L)
                        {
                                for(auto j: tmp)
                                {
                                        if (j == i or ghadr(a[i], a[j]) > x) continue;
                                        dp[mask][i][x] += dp[mask-two[i-1]][j][x-ghadr(a[i], a[j])];
                                }
                        }
                }
        }
        ll ans = 0;
        FOR(i, 1, n)
        {
                ans += dp[(1<<n)-1][i][L];
        }
        cout << ans%mod;






        return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 0 / 15
• Subtask 3: 0 / 80