Submission #1258562

#	Time	Username	Problem	Language	Result	Execution time	Memory
1258562		haiphong5g0	Festival (IOI25_festival)	C++20	0 / 100	47 ms	11956 KiB

festival

//#include "souvenirs.h"
#include <bits/stdc++.h>
#define task "TEST"
#define task2 "A"
#define pl pair<ll, ll>
#define pf push_front
#define pb push_back
#define pob pop_back
#define pof pop_front
#define mp make_pair
#define fi first
#define se second
#define FOR(i, a, b, c) for (int i=a; i<=b; i+=c)
#define FORE(i, a, b, c) for (int i=a; i>=b; i+=c)
using namespace std;
using ll = long long;
using Knowledge = pair<vector<int>, ll>;
using ull = unsigned long long;
const int Mod = 998244353;
const int maxn = 3e5;
const ll Inf = 1e16;
ll n, a, s;
vector<int> P, T;
struct Coupon {
    ll p, num;
    ll pos;
    bool operator > (Coupon other) const {
        return p*num*other.num + other.p*other.num <
               other.p*other.num*num + p*num;
    };
};
vector<Coupon> C[5];
ll Fix(ll& i, ll& j, ll& k, ll& h, ll pos, ll add) {
    ll v;
    if (pos == 1) i += add, v = i;
    if (pos == 2) j += add, v = j;
    if (pos == 3) k += add, v = k;
    if (pos == 4) h += add, v = h;
    return v;
}
vector<int> max_coupons(int s, vector<int> P, vector<int> T) {
    vector<Coupon> S[3]; vector<int> res;
    FOR(i, 0, P.size()-1, 1) {
        if (T[i] == 1) S[1].pb({P[i], T[i], i});
        else S[2].pb({P[i], T[i], i});
    }
    sort(S[2].begin(), S[2].end(), greater<Coupon>());
    ll m = (ll)C[1].size(), n = (ll)C[2].size();
    ll ans, sum[maxn+1], resrn = s, pos = -1;
    FOR(i, 0, m-1, 1) sum[i] = (i == 0 ? C[1][0].p : C[1][i].p + sum[i-1]);
    ans = upper_bound(sum, sum + m, resrn) - sum;
    FOR(i, 0, n-1, 1) {
        resrn = (resrn - C[2][i].p) * 2;
        if (resrn < 0) break;
        if (resrn > Inf) resrn = Inf;
        ll v = i + 1 + (upper_bound(sum, sum + m, resrn) - sum);
        if (v > ans) pos = i, ans = v;
    }
    vector<int> ret; ret.clear();
    FOR(i, 0, pos, 1) ret.pb(C[2][i].pos);
    FOR(i, 0, ans-pos-2, 1) ret.pb(C[1][i].pos);
    return ret;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 5
• Subtask 2: 0 / 7
• Subtask 3: 0 / 12
• Subtask 4: 0 / 15
• Subtask 5: 0 / 27
• Subtask 6: 0 / 16
• Subtask 7: 0 / 18