Submission #1254863

#	Time	Username	Problem	Language	Result	Execution time	Memory
1254863		Timosh	Souvenirs (IOI25_souvenirs)	C++20	4 / 100	0 ms	412 KiB

souvenirs

#include <bits/stdc++.h>
#include "souvenirs.h"

using namespace std;
#define ll long long

void buy_souvenirs(int n, long long P0)
{
    vector<ll> p(n), used(n);
    p[0] = P0;
    vector<pair<vector<int>, ll>> mp;
    map<ll, pair<vector<int>, ll>> ehh;
    auto ch = [&](ll x) -> pair<vector<int>, ll>
    {
        if (ehh.count(x))
            return ehh[x];
        pair<vector<int>, ll> hm = transaction(x);
        for (auto &i : hm.first)
            used[i]++;
        hm.second = x - hm.second;
        mp.push_back(hm);
        return ehh[x] = hm;
    };
    auto rec = [&](auto rec, int i) -> void
    {
        if (i == n - 1)
            return;
        pair<vector<int>, ll> cur;
        ll s = p[i] - 1;
        int sz = 2;
        while (1)
        {
            cur = ch(s);
            s -= cur.second;
            sz = cur.first.size();
            if (sz == 1)
                break;
            s = s / sz;
        }
        p[cur.first[0]] = s, rec(rec, cur.first[0]);
        for (auto &x : mp)
        {
            int s = x.second, c = 0, j = 0;
            for (auto &i : x.first)
            {
                if (p[i] == 0)
                    c++, j = i;
                s -= p[i];
            }
            if (c == 1)
                p[j] = s;
        }
        int last = i;
        for (int j = i; j < cur.first[0]; j++)
        {
            if (p[j] == 0)
                ch(p[last] - 1);
            else
                last = i;
        }
        for (auto &x : mp)
        {
            int s = x.second, c = 0, j = 0;
            for (auto &i : x.first)
            {
                if (p[i] == 0)
                    c++, j = i;
                s -= p[i];
            }
            if (c == 1)
                p[j] = s;
        }
    };
    rec(rec, 0);
    for (int i = 0; i < n; i++)
        for (int j = used[i]; j < i; j++)
            transaction(p[i]);
    return;
}

• Subtask 0: 0 / 0
• Subtask 1: 4 / 4
• Subtask 2: 0 / 3
• Subtask 3: 0 / 14
• Subtask 4: 0 / 18
• Subtask 5: 0 / 28
• Subtask 6: 0 / 33