Submission #1253789

#TimeUsernameProblemLanguageResultExecution timeMemory
1253789ender_shayanWatching (JOI13_watching)C++20
100 / 100
106 ms16952 KiB
#include <bits/stdc++.h>

using namespace std;

// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/tree_policy.hpp>
// using namespace __gnu_pbds;

typedef long long ll;
typedef long double	ld;
typedef pair<int, int>	pii  ;
typedef pair<ll, ll>	pll  ;
typedef vector<pii>     vii  ;
typedef vector<int>     veci ;
typedef vector<pll>     vll  ;
typedef vector<ll>      vecll;

// find_by_order             order_of_key

//#pragma GCC optimize("O3,unroll-loops")
//#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define F		        first
#define S		        second
#define pb		        push_back
#define endl            '\n'
#define Mp		        make_pair
#define all(x)          x.begin(), x.end()
#define debug(x)        cerr << #x << " = " << x << endl
#define set_dec(x)	    cout << fixed << setprecision(x);
#define fast_io         ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file_io         freopen("in.txt" , "r" , stdin) ; freopen("out.txt" , "w" , stdout);
#define lb              lower_bound
#define ub              upper_bound
#define for1(n)         for(int i=1;i<=n;i++)
#define for0(n)         for(int i=0;i<n;i++)
#define forn(n)         for(int i=n;i>0;i--)
#define pq              priority_queue <pii, vector<pii>, greater<pii>>


const ll mod = 1e9+7 ;// 998244353 ;// 1e9+9;

ll inf=1e18;
const int N=2e3+100,L=21,bs=701;
int A[N],B[N],C[N],D[N],E[N],n,m,k,q,p,dp[N][N],pre[N],dist[N],vis[N];
vector<int>g[N];

bool check(int w){
    for(int i=2;i<=n+1;i++)for(int j=0;j<=p;j++)dp[i][j]=q+1;
    for(int i=1;i<=n;i++){
        int t1=lb(A+i,A+n+1,A[i]+w)-A;
        int t2=lb(A+i,A+n+1,A[i]+w*2)-A;
        for(int j=0;j<=p;j++){
            dp[t1][j+1]=min(dp[t1][j+1],dp[i][j]);
            dp[t2][j]=min(dp[t2][j],dp[i][j]+1);
        }
    }
    return (dp[n+1][p]<=q);
}
int main(){
    fast_io
    cin>>n>>p>>q;
    if(p+q>=n)return cout<<"1\n",0;
    for1(n)cin>>A[i];
    sort(A+1,A+n+1);
    int l=0,r=mod/(p+q*2);
    while(r-l!=1){
        int mid=(l+r)>>1;
        if(check(mid)==0)l=mid;
        else r=mid;
    }
    cout<<l+1<<endl;

}



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