Submission #1247994

#	Time	Username	Problem	Language	Result	Execution time	Memory
1247994		al95ireyiz	Bouquet (EGOI24_bouquet)	C++20	100 / 100	67 ms	20212 KiB

Main

//*** Bismillah ***//
#pragma GCC optimize("O3", "fast-math", "unroll-loops", "no-stack-protector")
#include <bits/stdc++.h>
using namespace std;
#if !defined(ONLINE_JUDGE) and !defined(EVAL)
#include "template/debug.h"
#else
#define d(x...)
#endif
#define fr first
#define er erase
#define sc second
#define in insert
#define ll long long
#define pb push_back
#define vll vector<ll>
#define pll pair<ll,ll>
#define ull unsigned ll
#define vpll vector<pll>
#define len(x) (ll) x.size()
#define all(x) x.begin(),x.end()
const ll INF = 1e9;
const ll INFL = 1e18;
const ll MOD = 1e9+7;
// const ll MOD = 998244353;
const ll maxn = 2e5+5;
ll n,m,k=0;
ll l[maxn], r[maxn], dp[maxn], tree[4 * maxn];
void upd(ll x, ll val, ll l = 1, ll r = n, ll v = 1){
    if(l == r){
        tree[v] = val;
        return;
    }
    ll md = (l + r) >> 1;
    if(x <= md) upd(x, val, l, md, v << 1);
    else upd(x, val, md + 1, r, v << 1 | 1);
    tree[v] = max(tree[v << 1], tree[v << 1 | 1]);
}
ll get(ll _l, ll _r, ll l = 1, ll r = n, ll v = 1){
    bool in = _l <= l and r <= _r;
    bool ot = _l <= r and l <= _r;
    if(in) return tree[v];
    if(ot){
        ll md = (l + r) >> 1;
        return max(get(_l, _r, l, md, v << 1), get(_l, _r, md + 1, r, v << 1 | 1));
    }
    return 0;
}
vpll v[maxn];
void _(ll &tt){
    cin >> n;
    for(ll i = 1; i <= n; i ++) cin >> l[i] >> r[i], l[i] = min(l[i], i - 1), r[i] = min(r[i], n - i), v[i].clear();
    // if(max(l[i], r[j]) < i - j){
    // if(max(l[i] - i + j, r[j] - i + j) < 0){
    // if(l[i] - i + j < 0 ve r[j] - i + j < 0){
    // if(l[i] + (j - i) < 0 ve r[j] + (j - i) < 0){
    // if(i - l[i] > j >= 1 ve r[j] + j < i <= n){
    // j -> [1, i - l[i] - 1] ve i -> [r[j] + j + 1, n]
    ll mx = 0;
    for(ll i = 1; i <= n; i ++){
        for(auto [x, val] : v[i]){
            upd(x, val);
        }
        dp[i] = get(1, i - l[i] - 1) + 1;
        v[r[i] + i + 1].pb({i, dp[i]});
        mx = max(mx, dp[i]);
        d(dp[i]);
    }
    cout << mx << '\n';
}
signed main() {
    ll tm = clock();
    cin.tie(0)->sync_with_stdio(0);
    ll t = 1;
    // cin >> t;
    for(ll tt = 1; tt <= t; tt ++) {
        _(tt);
    }
    cerr << "\n\033[1;31mTime: \033[1;30m" \
         << (double)(clock()-tm)/1000000 << "\033[1;32m seconds\n";
}

• Subtask 1: 8 / 8
• Subtask 2: 16 / 16
• Subtask 3: 28 / 28
• Subtask 4: 18 / 18
• Subtask 5: 30 / 30