Submission #1245426

#TimeUsernameProblemLanguageResultExecution timeMemory
1245426PekibanBeech Tree (IOI23_beechtree)C++20
58 / 100
2098 ms58436 KiB
#include "beechtree.h" #include <bits/stdc++.h> using namespace std; using ll = long long; #define pb push_back mt19937_64 rng(time(0)); const int N = 2e5 + 5; bool ok[N]; vector<array<int, 2>> ch[N]; ll cl[N]; int sz[N], c[N]; void dfs(int s) { set<int> st; ok[s] = 1, sz[s] = 1; for (auto [u, w] : ch[s]) { if (st.count(w)) ok[s] = 0; st.insert(w); dfs(u); sz[s] += sz[u], ok[s] &= ok[u]; } } void dfscnt(int s, map<int, int> &f) { for (auto [u, w] : ch[s]) { f[w]++; dfscnt(u, f); } } bool chk(int s) { map<int, int> f; ll h[sz[s]]; fill(h, h+sz[s], 0); dfscnt(s, f); for (auto [x, y] : f) { // if (s == 0) cout << x << 'z' << y << endl; for (int i = 0; i < y; ++i) h[i] ^= cl[x]; } map<int, int> t, t2, t3; set<array<ll, 4>> st; ll xx = 0; for (auto [u, w] : ch[s]) { xx ^= cl[w]; // if (s == 0) cout << w << '|'; ll x = 0; for (auto [v, W] : ch[u]) x ^= cl[W]; t[u] = t2[w]; t2[w]++; st.insert({x, -sz[u], t[u], u}); } // if (s == 0) cout << xx << ' ' << h[0] << endl; if (xx != h[0]) return 0; // if (s == 2) { // for (auto [p, q, r, t] : st) cout << p << ' ' << q << ' ' << r << '\n'; // cout << h[1] << 't' << h[2] << '\n'; // for (auto [x, y] : f) { // cout << x << " " << y << '\n'; // } // } for (int i = 1; i < sz[s]; ++i) { auto it = st.lower_bound({h[i], (int)-1e9, 0, 0}); if ((*it)[0] != h[i]) return 0; int x = (*it)[3]; it = st.erase(it); // if (s == 2) cout << x << ' ' << t[x] << ' ' << ' ' << t3[c[x]] << '\n'; if (t[x] != t3[c[x]]) return 0; t3[c[x]]++; for (auto [u, w] : ch[x]) { ll xx = 0; for (auto [v, W] : ch[u]) xx ^= cl[W]; t[u] = t2[c[u]]; t2[c[u]]++; // if (s == 4) cout << xx << 'z' << u << '\n'; st.insert({xx, -sz[u], t[u], u}); } } return 1; } vector<int> beechtree(int n, int m, vector<int> P, vector<int> C) { for (int i = 1; i < n; ++i) ch[P[i]].pb({i, C[i]}); for (int i = 1; i <= m; ++i) cl[i] = rng() % (1LL << 62); for (int i = 1; i < n; ++i) c[i] = C[i]; dfs(0); vector<int> ans(n); for (int i = 0; i < n; ++i) ans[i] = (ok[i] ? chk(i) : 0); return ans; }
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