Submission #1243537

#	Time	Username	Problem	Language	Result	Execution time	Memory
1243537		longgggg	Crocodile's Underground City (IOI11_crocodile)	C++17	0 / 100	0 ms	320 KiB

crocodile

#include <bits/stdc++.h>
#define Longgggg ios_base::sync_with_stdio(0); cin.tie(0);
#define ll long long
#define endl '\n'
using namespace std;
// Bitwise
#define MASK(i) (1LL << (i))
#define BIT(x, i) (1LL & ((x) >> (i)))
#define ON(x, i) ((x) | MASK(i))
#define OFF(x, i) ((x) & ~MASK(i))
#define LASTBIT(mask) ((mask) & -(mask))
// Other
#define FOR(i, a, b) for (int i = (a); i <= (b); i++)
#define FORD(i, a, b) for (int i = (a); i >= (b); i--)
#define mod(x, k) ((((x) % (k)) + (k)) % (k))
#define all(x) begin(x), end(x)
#define fi first
#define se second

#define IN "A.in"
#define OUT "A.out"
#define DEBUG "debug.out"


const int INF = (int) 1e9+5;
const ll LINF = (ll) 1e18;
const ll MOD = (ll) 1e9+7;
const int mxN = 100005;


ll travel_plan(int N, int M, int R[][2], int L[], int K, int P[]) {
    int n = N, m = M, k = K;

    vector <vector <pair <int, int>>> adj(n);
    FOR(i, 0, m-1) {
        adj[R[i][0]].push_back({R[i][1], L[i]});
        adj[R[i][1]].push_back({R[i][0], L[i]});
    }

    // Dijkstra from exits
    priority_queue <pair <ll, ll>, vector <pair <ll, ll>>, greater<>> q;
    vector <pair <ll, ll>> d(n, {LINF, LINF}); // Two shortest distance
    FOR(i, 0, k-1) {
        q.push({0, P[i]});
        d[P[i]] = {0, 0};
    }

    while (!q.empty()) {
        ll u = q.top().se, dis = q.top().fi; 
        q.pop();

        if (dis > d[u].se) continue;
        for (auto &x : adj[u]) {
            ll v = x.fi, w = x.se;
            
            if (d[v].fi > dis + w) { // Shortest distance
                if (d[u].se < d[u].fi) q.push({d[v].fi, v});
                d[v].se = d[v].fi;
                d[v].fi = dis + w;
            }
            else if (d[v].se > dis + w) {
                d[v].se = dis + w; // Second shortest distance
                q.push({d[v].se, v});
            }
        }
    }

    return d[0].se;
}

• Subtask 1: 0 / 46
• Subtask 2: 0 / 43
• Subtask 3: 0 / 11