#include<bits/stdc++.h>
#define int long long
using namespace std;
#define For(i,a,b) for(int i = (a); i <= (b); ++i)
const int N = 5e5 + 1;
vector<int> g[N];
struct Node
{
int r,id;
};
vector<Node> quer[N];
pair<int,int> st[4*N];int lazy[4*N],ans[N],a[N],n;
void Push(int id, int l, int r)
{
if(!lazy[id]) return;
st[id].first = max(st[id].first,st[id].second+lazy[id]);
if(l != r)
{
lazy[2*id] = max(lazy[2*id],lazy[id]);
lazy[2*id+1] = max(lazy[2*id+1],lazy[id]);
}
lazy[id] = 0;
}
pair<int,int> Merge(pair<int,int> a, pair<int,int> b)
{
return {max(a.first,b.first),max(a.second,b.second)};
}
void build(int id, int l, int r)
{
if(l > r) return;
if(l == r)
{
st[id] = {a[l],a[l]};
return;
}
int mid = (l+r)/2;
build(2*id,l,mid);
build(2*id+1,mid+1,r);
st[id] = Merge(st[2*id],st[2*id+1]);
}
void update(int id, int l, int r, int u, int v, int val)
{
Push(id,l,r);
if(l > r) return;
if(l > v || r < u) return;
if(u <= l && r <= v)
{
lazy[id] = max(val,lazy[id]);
Push(id,l,r);
return;
}
int mid = (l+r)/2;
update(2*id,l,mid,u,v,val);
update(2*id+1,mid+1,r,u,v,val);
st[id] = Merge(st[2*id],st[2*id+1]);
}
int get(int id, int l, int r, int u, int v)
{
Push(id,l,r);
if(l > v || r < u) return 0;
if(u <= l && r <= v) {return st[id].first;}
int mid = (l+r)/2;
Push(id,l,r);
return max(get(2*id,l,mid,u,v),get(2*id+1,mid+1,r,u,v));
}
int32_t main()
{
// freopen("kien.inp","r",stdin);
// freopen("kien.out","w",stdout);
ios_base::sync_with_stdio(0);
cin.tie(0);cout.tie(0);
cin >> n;
vector<int> st;
For(i,1,n)
{
cin >> a[i];
while(!st.empty() && a[i] >= a[st.back()])
{
g[st.back()].push_back(i);
st.pop_back();
}
if(!st.empty()) g[st.back()].push_back(i);
st.push_back(i);
}
build(1,1,n);
int q;
cin >> q;
For(i,1,q)
{ int l,r;
cin >> l >> r;
quer[l].push_back({r,i});
}
for(int i = n-2; i >= 1; i--)
{
//cout << i << endl;
for(int id : g[i])
{ //cout << i <<' ' <<id <<' ' << a[i] + a[id] << endl;
update(1,1,n,2*id-i,n,a[i]+a[id]);
}
for(auto [r,id] : quer[i])
{
ans[id] = get(1,1,n,i,r);
// if(i == 1)
// {
// //cout << i << ' ' << get(1,1,n,9,9) << endl;
// }
}
}
For(i,1,q) cout << ans[i] <<'\n';
}
