Submission #1239856

#	Time	Username	Problem	Language	Result	Execution time	Memory
1239856		Minbaev	Knapsack (NOI18_knapsack)	C++20	100 / 100	73 ms	2888 KiB

knapsack

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>

#pragma GCC target("avx,avx2,fma")
#pragma GCC optimize("Ofast,unroll-loops")

using namespace std;
using namespace __gnu_pbds;

#define pb      push_back
#define all(x)  x.begin(),x.end()
#define int     long long
#define ar      array
#define mrand(a, b)   uniform_int_distribution<int>(a, b)(rng)

template<class T>bool umax(T &a,T b){if(a<b){a=b;return true;}return false;}
template<class T>bool umin(T &a,T b){if(b<a){a=b;return true;}return false;}

template<class T> using ste = tree<T, null_type, less_equal<T>,
rb_tree_tag, tree_order_statistics_node_update>;

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

namespace FAST {
    template<typename T, typename F>
    istream &operator>>(istream &cin, pair<T, F> &p) {
        cin >> p.first >> p.second;
        return cin;
    }

    template<typename T, typename F>
    ostream &operator<<(ostream &cout, pair<T, F> &p) {
        cout << p.first << ' ' << p.second;
        return cout;
    }

    template<typename T>
    istream &operator>>(istream &cin, vector<T> &a) {
    for (T &i: a) cin >> i;
        return cin;
    }

    template<typename T>
    ostream &operator<<(ostream &cout, vector<T> &a) {
          for (T i: a) cout << i << ' ';
        return cout;
    }

    template<typename T>
    istream &operator>>(istream &cin, deque<T> &a) {
        for (T &i: a) cin >> i;
        return cin;
    }

    template<typename T>
    ostream &operator<<(ostream &cout, deque<T> &a) {
        for (T i: a) cout << i << ' ';
        return cout;
    }
}
using namespace FAST;

const int inf = 1e17 + 7;
const int mod = 1e9 + 7;
const int N = 1e6 + 5;
const int md = 998244353;

int binpow(int a, int b, int m){
    if(b == 0)return 1;
    if(b % 2 == 0){
        int c = binpow(a,b/2,m);
        return (c*c)%m;
    }
    return (binpow(a,b-1,m)*a)%m;
}

int divi(int a, int b, int m){
    return (a*(binpow(b,m-2, m)))%m;
}

struct Bit {
    vector<int> b, b2;
    int n;

    Bit(int n) {
        this->n = n + 1;
        b.assign(n + 1, 0);
        b2.assign(n+1, 0);
    }

    void add(vector<int>&b, int idx, int x){
        while(idx <= n){
            b[idx] += x;
            idx += idx & -idx;
        }
    }

    void update(int l, int r, int x){
        add(b, l, x);
        add(b, r+1, -x);
        add(b2, l, x*(l-1));
        add(b2, r+1, -x*r);
    }

    int sum(vector<int>&b, int idx){
        int res = 0;
        while(idx > 0){
            res += b[idx];
            idx -= idx & -idx;
        }
        return res;
    }

    int pref(int idx){
        return sum(b, idx) * idx - sum(b2, idx);
    }

    int get(int l, int r){                  
        return pref(r) - pref(l-1);
    }
};

int n,m,k;
vector<ar<int,2>>g[2005];

void solve(){

    cin >> m >> n;
    for(int i = 0;i<n;i++){
        int a,b,c;
        cin >> a >> b >> c;
        g[b].pb({a, c});
    }

    vector<int>dp(2005);

    for(int i = 1;i<=m;i++){
        sort(all(g[i]));
        reverse(all(g[i]));
        int u = m / i;
        int cont = 0; 

        for(auto [cost, cnt]:g[i]){
            while(cont < u && cnt > 0){
                cnt -= 1;
                cont += 1;
                for(int j = m;j>=0;j--){
                    if(j + i > m)continue;
                    if(dp[j] > 0 || j == 0)
                        umax(dp[j + i], dp[j] + cost);
                }
            }
        }
    }


    cout << *max_element(all(dp)) << "\n";





}
/*

*/
 signed main()
{
//  freopen("seq.in", "r", stdin);
//  freopen("seq.out", "w", stdout);
    ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL);
    int tt=1;// cin >> tt;
    while(tt--)solve();

}

• Subtask 1: 12 / 12
• Subtask 2: 17 / 17
• Subtask 3: 20 / 20
• Subtask 4: 24 / 24
• Subtask 5: 27 / 27