제출 #1236814

#제출 시각아이디문제언어결과실행 시간메모리
1236814fauntleroySterilizing Spray (JOI15_sterilizing)C++20
100 / 100
119 ms4680 KiB
#include <iostream>
#include <cstdio>
#include <vector>
#include <array>
#include <string>
#include <algorithm>
#include <numeric>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <queue>
#include <cmath>
#include <climits>
#include <iomanip>
#include <limits>
#include <tuple>
#include <stack>
#include <bitset>
#include <cstring>
#include <sstream>
#include <functional>
#include <random>
#define int long long
using namespace std;

int n;
vector<int>a;
vector<int> seg;

void build(int u, int l, int r) {
    if (l == r)
        seg[u] = a[l];
    else {
        int mid = (l + r) >> 1;
        build(u << 1, l, mid);
        build(u << 1 | 1, mid + 1, r);
        seg[u] = seg[u << 1] + seg[u << 1 | 1];
    }
}

void p_upd(int u, int l, int r, int idx, int val) {
    if (l == r) {
        seg[u] += val;
        a[idx] += val;
    }
    else {
        int mid = (l + r) >> 1;
        if (idx <= mid)
            p_upd(u << 1, l, mid, idx, val);
        else
            p_upd(u << 1 | 1, mid + 1, r, idx, val);
        seg[u] = seg[u << 1] + seg[u << 1 | 1];
    }
}

void div(int u, int l, int r, int ql, int qr, int k) {
    if (r<ql || l>qr || seg[u] == 0)
        return;
    if (l == r)
        seg[u] /= k, a[l] /= k;
    else {
        int mid = (l + r) >> 1;        
        div(u << 1, l, mid, ql, qr, k);
        div(u << 1 | 1, mid + 1, r, ql, qr, k);
        seg[u] = seg[u << 1] + seg[u << 1 | 1];
    }
}

int query(int u, int l, int r, int ql, int qr) {
    if (r<ql || l>qr)
        return 0;
    if (ql <= l && r <= qr)
        return seg[u];
    int mid = (l + r) >> 1;
    return query(u << 1, l, mid, ql, qr) + query(u << 1 | 1, mid + 1, r, ql, qr);
}

void solve() {
    int n, q, k;
    cin >> n >> q >> k;
    a.resize(n);
    seg.resize(4 * n);
    for (auto& e : a)
        cin >> e;
    build(1, 0, n - 1);
    while (q--) {
        int s, t, u;
        cin >> s >> t >> u;
        if (s == 1)
            p_upd(1, 0, n - 1, t - 1, u - a[t - 1]);
        else if (s == 2) {
            if (k != 1)
                div(1, 0, n - 1, t - 1, u - 1, k);
        }
        else
            cout << query(1, 0, n - 1, t - 1, u - 1) << '\n';
    }
}

signed main() {
    ios::sync_with_stdio(false);
    cin.tie(nullptr);
    solve();
    return 0;
}
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