Submission #1233499

#	Time	Username	Problem	Language	Result	Execution time	Memory
1233499		antonn	Soccer Stadium (IOI23_soccer)	C++20	48 / 100	4648 ms	1024312 KiB

soccer

#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;

typedef long long ll;

const int N = 500 + 7;

int a[N][N], pref[N][N], dp[2][N][N][N];

bool ok(int l, int x, int y) {
    return pref[l][y] - pref[l][x - 1] == 0;
}

int biggest_stadium(int n, vector<vector<int>> f) {
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= n; ++j) {
            a[i][j] = f[i - 1][j - 1];
            pref[i][j] = pref[i][j - 1] + a[i][j];
        }
    }
    for (int down = 0; down < N; ++down) {
        for (int x = 0; x < N; ++x) {
            for (int y = x; y < N; ++y) {
                dp[0][down][x][y] = -1e9;
                dp[1][down][x][y] = -1e9;
            }
        }
    }
    for (int i = 1; i <= n; ++i) {
        for (int l = 1; l <= n; ++l) {
            for (int r = l; r <= n; ++r) {
                if (ok(i, l, r)) dp[1][i][l][r] = r - l + 1;
            }
        }
    }
    int ans = 0;
    for (int h2 = 1; h2 <= n; ++h2) {
        for (int down = 1; down + h2 - 1 <= n; ++down) {
            int up = down + h2 - 1;
            
            
            for (int l = n; l >= 1; --l) {
                for (int r = l; r <= n; ++r) {
                    ans = max(ans, dp[h2 % 2][down][l][r]);
                    
                    // if (!ok(up, l, r)) break;
                    for (int x = l; x <= r; ++x) {
                        for (int y = x; y <= r; ++y) {
                            if (ok(down - 1, x, y)) {
                                dp[(h2 + 1) % 2][down - 1][x][y] = max(dp[(h2 + 1) % 2][down - 1][x][y], dp[h2 % 2][down][l][r] + y - x + 1);
                            } else {
                                break;
                            }
                        }
                        for (int y = x; y <= r; ++y) {
                            if (ok(up + 1, x, y)) {
                                dp[(h2 + 1) % 2][down][x][y] = max(dp[(h2 + 1) % 2][down][x][y], dp[h2 % 2][down][l][r] + y - x + 1);
                            } else {
                                break;
                            }
                        }
                    }
                    dp[h2 % 2][down][l][r] = -1e9;
                }
            }
        }
    }
    return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 6
• Subtask 2: 8 / 8
• Subtask 3: 22 / 22
• Subtask 4: 18 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30