Submission #1232488

#	Time	Username	Problem	Language	Result	Execution time	Memory
1232488		peyman_sf	Kemija (COCI22_kemija)	C++20	50 / 50	0 ms	328 KiB

Main

#include <bits/stdc++.h>

using namespace std;
typedef long long ll;
typedef long double ld;
typedef vector<ll> vll;
typedef pair<ll, ll> pll;

const ll maxn = 3e6;
const ll mod = 1e9 + 7;
const ll inf = 2e18;

#define TextIO ifstream fileIn("input.txt"); cin.rdbuf(fileIn.rdbuf()); ofstream fileOut("output.txt"); cout.rdbuf(fileOut.rdbuf());
#define FastIO ios_base::sync_with_stdio(false); cin.tie(NULL);
#define print(x) for (auto i : x) cout << i << ' '; cout << endl
#define out(x) {cout << x << endl; return;}
#define all(x) (x).begin(), (x).end()
#define pb push_back
#define endl '\n'

ll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b);}
ll lcm(ll a, ll b) { return (a * b) / gcd(a, b); }
ll pw(ll a, ll b, ll md = mod) {ll res = 1; b = max(b, 0ll); while(b) {if (b & 1){res = (a * res) % md;} a = (a * a) % md; b >>= 1;} return (res % md);}

void solve() {
    string s;
    cin >> s;
    s = "+" + s;
    ll t = 0;
    ll x = 1;
    map<char, ll> cnt, cnt2;
    ll i = 1;
    for (; i < s.size(); i++) {
        if (s[i] == '-') {
            i++;
            break;
        }
        else {
            ll d = (s[i] - '0');
            if (d >= 0 && d < 10)
                x = d;

            else {
                if (s[i] == '+')
                    x = 1;

                else {
                    if (i != s.size() - 1 && (s[i + 1] - '0') >= 0 && (s[i + 1] - '0') < 10) {
                        cnt[s[i]] += (s[i + 1] - '0') * x;
                        i++;
                    }
                    else
                        cnt[s[i]] += x;
                }
            }
        }
    }
    i++;
    for (; i < s.size(); i++) {
        ll d = (s[i] - '0');
        if (d >= 0 && d < 10)
            x = d;

        else {
            if (s[i] == '+')
                x = 1;

            else {
                if (i != s.size() - 1 && (s[i + 1] - '0') >= 0 && (s[i + 1] - '0') < 10) {
                    cnt2[s[i]] += (s[i + 1] - '0') * x;
                    i++;
                }
                else
                    cnt2[s[i]] += x;
            }
        }
    }

    if (cnt == cnt2) out("DA");
    cout << "NE" << endl;
}

int main() {
    FastIO
    ll t = 1;
    cin >> t;
    while (t--)
        solve();

    return 0;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 30 / 30