Submission #122592

#	Time	Username	Problem	Language	Result	Execution time	Memory
122592		duality	Bitaro, who Leaps through Time (JOI19_timeleap)	C++11	100 / 100	968 ms	63396 KiB

timeleap

#define DEBUG 0

#include <bits/stdc++.h>
using namespace std;

#if DEBUG
// basic debugging macros
int __i__,__j__;
#define printLine(l) for(__i__=0;__i__<l;__i__++){cout<<"-";}cout<<endl
#define printLine2(l,c) for(__i__=0;__i__<l;__i__++){cout<<c;}cout<<endl
#define printVar(n) cout<<#n<<": "<<n<<endl
#define printArr(a,l) cout<<#a<<": ";for(__i__=0;__i__<l;__i__++){cout<<a[__i__]<<" ";}cout<<endl
#define print2dArr(a,r,c) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<a[__i__][__j__]<<" ";}cout<<endl;}
#define print2dArr2(a,r,c,l) cout<<#a<<":\n";for(__i__=0;__i__<r;__i__++){for(__j__=0;__j__<c;__j__++){cout<<setw(l)<<setfill(' ')<<a[__i__][__j__]<<" ";}cout<<endl;}

// advanced debugging class
// debug 1,2,'A',"test";
class _Debug {
    public:
        template<typename T>
        _Debug& operator,(T val) {
            cout << val << endl;
            return *this;
        }
};
#define debug _Debug(),
#else
#define printLine(l)
#define printLine2(l,c)
#define printVar(n)
#define printArr(a,l)
#define print2dArr(a,r,c)
#define print2dArr2(a,r,c,l)
#define debug
#endif

// define
#define MAX_VAL 999999999
#define MAX_VAL_2 999999999999999999LL
#define EPS 1e-6
#define mp make_pair
#define pb push_back

// typedef
typedef unsigned int UI;
typedef long long int LLI;
typedef unsigned long long int ULLI;
typedef unsigned short int US;
typedef pair<int,int> pii;
typedef pair<LLI,LLI> plli;
typedef vector<int> vi;
typedef vector<LLI> vlli;
typedef vector<pii> vpii;
typedef vector<plli> vplli;

// ---------- END OF TEMPLATE ----------

int L[300000],R[300000];
int T[300000],A[300000],B[300000],C[300000],D[300000];
int l[300000],r[300000];
LLI ans[300000];
struct func {
    LLI a,b,c,p;
    plli eval(LLI x) {
        if (x > p) return mp(b,c+x-p);
        else return mp(max(b+x-p,a),c);
    }
};
func com(func a,func b) {
    func c;
    c.a = b.eval(a.a).first,c.b = b.eval(a.b).first;
    c.c = a.c+b.eval(a.a).second;
    c.p = min(a.p,a.p-a.b+max(b.p,a.a));
    return c;
}
func tree[1 << 20];
int build(int s,int e,int i) {
    if (s == e) {
        tree[i] = (func){l[s],r[s],0,r[s]};
        return 0;
    }

    int mid = (s+e) / 2;
    build(s,mid,2*i+1),build(mid+1,e,2*i+2);
    tree[i] = com(tree[2*i+1],tree[2*i+2]);
    return 0;
}
int update(int s,int e,int ai,int i) {
    if ((s > ai) || (e < ai)) return 0;
    else if (s == e) {
        tree[i] = (func){l[s],r[s],0,r[s]};
        return 0;
    }

    int mid = (s+e) / 2;
    update(s,mid,ai,2*i+1),update(mid+1,e,ai,2*i+2);
    tree[i] = com(tree[2*i+1],tree[2*i+2]);
    return 0;
}
func query(int s,int e,int qs,int qe,int i) {
    if ((s > qe) || (e < qs)) return (func){(LLI) -1e12,(LLI) 1e12,0,(LLI) 1e12};
    else if ((s >= qs) && (e <= qe)) return tree[i];

    int mid = (s+e) / 2;
    return com(query(s,mid,qs,qe,2*i+1),query(mid+1,e,qs,qe,2*i+2));
}
int main() {
    int i;
    int N,Q;
    scanf("%d %d",&N,&Q);
    for (i = 0; i < N-1; i++) scanf("%d %d",&L[i],&R[i]);
    for (i = 0; i < Q; i++) {
        scanf("%d",&T[i]);
        if (T[i] == 1) scanf("%d %d %d",&A[i],&B[i],&C[i]),A[i]--,ans[i] = -1;
        else {
            scanf("%d %d %d %d",&A[i],&B[i],&C[i],&D[i]),A[i]--,C[i]--;
            if (A[i] == C[i]) ans[i] = max(B[i]-D[i],0);
        }
    }

    int rr;
    for (rr = 0; rr < 2; rr++) {
        if (N == 1) break;
        for (i = 0; i < N-1; i++) l[i] = L[i]-i,r[i] = R[i]-i-1;
        build(0,N-2,0);
        for (i = 0; i < Q; i++) {
            if (T[i] == 1) {
                l[A[i]] = B[i]-A[i],r[A[i]] = C[i]-A[i]-1;
                update(0,N-2,A[i],0);
            }
            else if ((T[i] == 2) && (A[i] < C[i])) {
                func f = query(0,N-2,A[i],C[i]-1,0);
                plli p = f.eval(B[i]-A[i]);
                if (p.first > (D[i]-C[i])) p.second += p.first-(D[i]-C[i]);
                ans[i] = p.second;
            }
        }
        reverse(L,L+N-1),reverse(R,R+N-1);
        for (i = 0; i < Q; i++) {
            if (T[i] == 1) A[i] = N-2-A[i];
            else if (T[i] == 2) A[i] = N-1-A[i],C[i] = N-1-C[i];
        }
    }
    for (i = 0; i < Q; i++) {
        if (ans[i] != -1) printf("%lld\n",ans[i]);
    }

    return 0;
}

Compilation message (stderr)

timeleap.cpp: In function 'int main()':
timeleap.cpp:110:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d",&N,&Q);
     ~~~~~^~~~~~~~~~~~~~~
timeleap.cpp:111:36: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     for (i = 0; i < N-1; i++) scanf("%d %d",&L[i],&R[i]);
                               ~~~~~^~~~~~~~~~~~~~~~~~~~~
timeleap.cpp:113:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d",&T[i]);
         ~~~~~^~~~~~~~~~~~
timeleap.cpp:114:66: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         if (T[i] == 1) scanf("%d %d %d",&A[i],&B[i],&C[i]),A[i]--,ans[i] = -1;
                        ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~
timeleap.cpp:116:64: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
             scanf("%d %d %d %d",&A[i],&B[i],&C[i],&D[i]),A[i]--,C[i]--;
             ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~

• Subtask 1: 4 / 4
• Subtask 2: 30 / 30
• Subtask 3: 66 / 66