Submission #1223809

#	Time	Username	Problem	Language	Result	Execution time	Memory
1223809		Zbyszek99	Holiday (IOI14_holiday)	C++20	23 / 100	674 ms	8880 KiB

holiday

#include"holiday.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define ll long long
#define ld long double
#define ull unsigned long long
#define ff first
#define ss second
#define pii pair<int,int>
#define pll pair<long long, long long>
#define vi vector<int>
#define vl vector<long long>
#define pb push_back
#define rep(i, b) for(int i = 0; i < (b); ++i)
#define rep2(i,a,b) for(int i = a; i <= (b); ++i)
#define rep3(i,a,b,c) for(int i = a; i <= (b); i+=c)
#define count_bits(x) __builtin_popcountll((x))
#define all(x) (x).begin(),(x).end()
#define siz(x) (int)(x).size()
#define forall(it,x) for(auto& it:(x))
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set;
//mt19937 mt;void random_start(){mt.seed(chrono::time_point_cast<chrono::milliseconds>(chrono::high_resolution_clock::now()).time_since_epoch().count());}
//ll los(ll a, ll b) {return a + (mt() % (b-a+1));}
const int INF = 1e9+50;
const ll INF_L = 1e18+40;
const ll MOD = 1e9+7;

ll real_val[(1 << 17)];

struct node
{
    int l = 0;
    int r = (1<< 17)-1;
    node* left;
    node* right;
    ll sum = 0;
    int elms = 0;
    bool is_sons = 0;
    void upd()
    {
        if(!is_sons)
        {
            left = new node;
            left -> l = l;
            left -> r = (l+r)/2;
            right = new node;
            right -> l = (l+r)/2+1;
            right -> r = r;
        }
        is_sons = 1;
    }
    void change(int x, int d)
    {
        if(l == r)
        {
            sum += d*real_val[x];
            elms += d;
            return;
        }
        upd();
        if((l+r)/2 >= x) left -> change(x,d);
        else right -> change(x,d);
        sum = left -> sum + right -> sum;
        elms = left -> elms + right -> elms;
    }
    ll get_kth_sum(int k)
    {
        if(l == r)
        {
            return (ll)min(k,elms)*real_val[l];
        }
        upd();
        if(right -> elms >= k) return right -> get_kth_sum(k);
        else return right -> sum + left -> get_kth_sum(k-right->elms);
    }
};


int arr[100001];
ll left_val[2][250001];
ll right_val[2][250001];
node segtree;
int S,D;

void solve(int l, int r, int l_opt, int r_opt, int type, ll cost, ll* ansT)
{
    if(l > r) return;
    int mid = (l+r)/2;
    pll best = {-1e18,l_opt};
    if(type == -1)
    {
        for(int i = r_opt; i >= l_opt; i--)
        {
            segtree.change(arr[i],1);
            ll new_val = segtree.get_kth_sum(mid - cost*(S - i));
            if(new_val > best.ff)
            {
                best = {new_val,i};
            }
        }
        ansT[mid] = best.ff;
        rep2(i,l_opt,best.ss)
        {
            segtree.change(arr[i],-1);
        }
        solve(mid+1,r,l_opt,best.ss,type,cost,ansT);
        rep2(i,best.ss+1,r_opt)
        {
            segtree.change(arr[i],-1);
        }
        solve(l,mid-1,best.ss,r_opt,type,cost,ansT);
    }
    else
    {
        rep2(i,l_opt,r_opt)
        {
            segtree.change(arr[i],1);
            ll new_val = segtree.get_kth_sum(mid - cost*(i - S));
            if(new_val > best.ff)
            {
                best = {new_val,i};
            }
        }
        ansT[mid] = best.ff;
        rep2(i,best.ss,r_opt)
        {
            segtree.change(arr[i],-1);
        }
        solve(mid+1,r,best.ss,r_opt,type,cost,ansT);
        rep2(i,l_opt,best.ss-1)
        {
            segtree.change(arr[i],-1);
        }
        solve(l,mid-1,l_opt,best.ss,type,cost,ansT);
    }
}

ll findMaxAttraction(int n, int start, int d, int attraction[]) 
{
    rep(i,n) arr[i] = attraction[i];
    map<int,int> tree_val;
    vi ar2;
    rep(i,n) ar2.pb(arr[i]);
    sort(all(ar2));
    int pop = -1;
    int cur_ = 0;
    forall(it,ar2)
    {
        if(it != pop)
        {
            real_val[cur_] = it;
            tree_val[it] = cur_;
            cur_++;
        }
        pop = it;
    }
    rep(i,n) arr[i] = tree_val[arr[i]];
    D = d;
    S = start;
    solve(0,d,0,start,-1,1,left_val[0]);
    solve(0,d,0,start,-1,2,left_val[1]);
    solve(0,d,start+1,n-1,1,1,right_val[0]);
    solve(0,d,start+1,n-1,1,2,right_val[1]);
    ll ans = 0;
    rep2(i,0,d)
    {
        ans = max(ans,left_val[1][i]+right_val[0][d-i]);
        ans = max(ans,left_val[0][i]+right_val[1][d-i]);
    }
    return ans;
}

• Subtask 1: 0 / 7
• Subtask 2: 23 / 23
• Subtask 3: 0 / 17
• Subtask 4: 0 / 53