Submission #1222128

#	Time	Username	Problem	Language	Result	Execution time	Memory
1222128		thelegendary08	Beech Tree (IOI23_beechtree)	C++17	0 / 100	1 ms	324 KiB

beechtree

#include "beechtree.h"
#include<bits/stdc++.h>
#define int long long
#define f0r(i,n) for(int i = 0; i<n; i++)
#define pb push_back
#define mp make_pair
#define vi vector<int>
#define mii map<int,int>
#define pii pair<int,int>
#define vpii vector<pii>
#define FOR(i, k, n) for(int i = k; i<n; i++)
#define vb vector<bool>
using namespace std;
vector<vi>adj, colset, su;
vi dep, sts, die, diesum, tp;
vector<signed>ans;
int dfs(int node){
	int cur = 1;
	for(auto u : adj[node]){
		dep[u] = dep[node] + 1;
		cur += dfs(u);
	}
	sts[node] = cur;
	return cur;
}
int d2(int node){
	int cur = die[node];
	for(auto u : adj[node]){
		cur += d2(u);
	}
	diesum[node] = cur;
	return cur;
}
void d3(int node){
	if(sts[node] == 1){
		su[node][tp[node]]++; return;
	}
	for(auto u : adj[node]){
		f0r(j, 4){
			su[node][j] += su[u][j];
		}
	}
	su[node][tp[node]]++;
}
void solve(int node){
	if(sts[node] == 1){
		ans[node] = 1; return;
	}
	for(auto u : adj[node]){
		solve(u);
	}
	if(diesum[node] != 0){
		ans[node] = 0; return;
	}
	for(auto u : adj[node]){
		if(ans[u] == 0){
			ans[node] = 0; return;
		}
	}
	vi w = su[node];
	if(tp[node] == 1 && w[3] != 0){
		ans[node] = 0; return;
	}
	if(tp[node] == 2 && w[3] != 0){
		ans[node] = 0; return;
	}
	if(w[1] != 0 && w[2] != 0){
		ans[node] = 0; return;
	}
	ans[node] = 1; return;
	
}
std::vector<signed> beechtree(signed N, signed M, std::vector<signed> P, std::vector<signed> C)
{
	ans.resize(N);
	FOR(i, 1, N)ans[i] = 0;
	colset.clear(); colset.resize(N); adj.clear(); adj.resize(N); tp.clear(); tp.resize(N);
	dep.clear(); dep.resize(N); sts.clear(); sts.resize(N); die.clear(); die.resize(N); diesum.clear(); diesum.resize(N);
	FOR(i, 1, N){
		adj[P[i]].pb(i);
	}
	
	f0r(i, N){
		set<int>tmp;
		for(auto u : adj[i]){
			tmp.insert(C[u]); colset[i].pb(C[u]);
		}
		if(tmp.size() != colset[i].size()){
			die[i] = 1;
		}
		int sum = 0;
		for(auto u : tmp){
			sum += u;
		}
		tp[i] = sum;
	}
	dfs(0);
	d2(0);
	su.resize(N);
	f0r(i, N){
		su[i].resize(4);
	}
	d3(0);
	return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 9
• Subtask 2: 0 / 5
• Subtask 3: 0 / 9
• Subtask 4: 0 / 8
• Subtask 5: 0 / 14
• Subtask 6: 0 / 14
• Subtask 7: 0 / 12
• Subtask 8: 0 / 17
• Subtask 9: 0 / 12