Submission #1218636

#TimeUsernameProblemLanguageResultExecution timeMemory
1218636pauloaphKnapsack (NOI18_knapsack)C++20
17 / 100
2 ms1864 KiB
#include<iostream> #include<algorithm> #include <cmath> using namespace std; const int MAXN = 100000; const int MAXC = 1000; int main(){ int C; int n; cin >> C >> n; int V[n]; int W[n]; int B[n]; for (int i = 0; i < n; i++){ cin >> V[i] >> W[i] >> B[i]; } long int NW[MAXN]; long int NV[MAXN]; long int M = 0; // vamos criar os novos itens (pacotes) for ( int i = 0; i < n; ++i ){ int pos = 0; // procuramos o bit mais significativo while ( (1 << pos) < B[i] ) pos++; // aqui sabemos que (2 ^ pos) >= B[i] pos--; // agora 2 ^ pos < B[i], logo (2 ^ pos) - 1 <= B[i] while ( pos >= 0 ){ NW[M] = (1 << pos) * W[i]; NV[M] = (1 << pos) * V[i]; B[i] -= (1 << pos); M++; pos--; } if ( B[i] ){ // se sobrou um resto NW[M] = B[i] * W[i]; NV[M] = B[i] * V[i]; M++; B[i] = 0; } } // caso base : quando nao temos mais itens long int dp[2][C+2]; int prev = 0, act = 1; // caso base : quando nao temos mais itens for ( int c = 0; c <= C; ++c ) dp[prev][c] = 0; for ( int i = M - 1; i >= 0; --i ){ for ( int c = 0; c <= C; ++c ){ dp[act][c] = dp[prev][c]; if ( NW[i] <= c ) { dp[act][c] = max( dp[act][c], dp[prev][c - NW[i]] + NV[i] ); } } swap( act, prev ); } cout << dp[prev][C] << endl; return 0; }
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