Submission #1218183

#	Time	Username	Problem	Language	Result	Execution time	Memory
1218183		vanea	Catfish Farm (IOI22_fish)	C++20	9 / 100	967 ms	2162688 KiB

fish

#include <bits/stdc++.h>
#include "fish.h"
using namespace std;
using ll = long long;

int n, m;

ll max_weights(int N, int M, vector<int> X, vector<int> Y, vector<int> W) {
    n = N; m = M;
    bool f = true, s = true, t = true;
    for(int i = 0; i < m; i++) {
        if(X[i] & 1) f = false;
        if(X[i] > 1) s = false;
        if(Y[i] != 0) t = false;
    }
    if(f) {
        ll ans = 0;
        for(int i = 0; i < m; i++) ans += W[i];
        return ans;
    }
    if(s) {
        ll f1 = 0, s1 = 0;
        vector<ll> pref(n+1);
        for(int i = 0; i < m; i++) {
            if(X[i] == 0) f1 += W[i];
            else s1 += W[i];
        }
        if(n <= 2) return max(f1, s1);
        vector<ll> pref1(n+1), pref2(n+1);
        for(int i = 0; i < m; i++) {
            if(X[i] == 0) pref1[Y[i]] += W[i];
            else pref2[Y[i]] += W[i];
        }
        ll ans = max(f1, s1);
        for(int i = 1; i <= n; i++) {
            pref1[i] += pref1[i-1];
            pref2[i] += pref2[i-1];
        }
        for(int i = 0; i < n; i++) {
            ans = max(ans, s1-pref2[i]+pref1[i]);
        }
        return ans;
    }
    vector<ll> pref1(n+1), pref2(n+1);
    vector<vector<array<ll, 2>>> adj(n+1);
    for(int i = 0; i < m; i++) {
        adj[X[i]].push_back({Y[i]+1, W[i]});
        if(X[i] == 0) pref1[Y[i]+1] += W[i];
        if(X[i] == 1) pref2[Y[i]+1] += W[i];
    }
    for(int i = 2; i <= n; i++) {
        pref1[i] += pref1[i-1];
        pref2[i] += pref2[i-1];
    }
    vector<vector<array<ll, 2>>> dp(n+1, vector<array<ll, 2>>(n+1));
    ll ans = 0;
    for(int j = 0; j <= n; j++) {
        for(int k = 0; k <= n; k++) {
            if(k > j) {
                dp[1][j][1] = max({dp[1][j][1], pref2[k]-pref2[j]});
            }
            else if(k < j){
                dp[1][j][0] = max(dp[1][j][0], pref1[j]-pref1[k]);
                dp[1][j][1] = max(dp[1][j][1], pref1[j]-pref1[k]);
            }
        }
        ans = max({ans, dp[1][j][0], dp[1][j][1]});
    }
    for(int i = 2; i < n; i++) {
        swap(pref1, pref2);
        for(int j = 0; j <= n; j++) pref2[j] = 0;
        for(auto [y, w] : adj[i]) pref2[y] = w;
        for(int j = 1; j <= n; j++) pref2[j] += pref2[j-1];
        for(int j = 0; j <= n; j++) {
            for(int k = 0; k <= n; k++) {
                if(k == j) continue;
                if(k > j) {
                    dp[i][j][1] = max({dp[i][j][1], dp[i-1][k][1] + pref2[k] - pref2[j],
                                      dp[i-1][k][0] + pref2[k] - pref2[j]});

                }
                else {
                    dp[i][j][0] = max({dp[i][j][0],
                                      dp[i-1][k][0]+pref1[j]-pref1[k],
                                      dp[i-1][k][1]});
                }
            }
            ans = max({ans, dp[i][j][0], dp[i][j][1]});
        }
    }
    return ans;
}

• Subtask 1: 3 / 3
• Subtask 2: 6 / 6
• Subtask 3: 0 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16