Submission #1214759

#TimeUsernameProblemLanguageResultExecution timeMemory
1214759alterioTorrent (COI16_torrent)C++20
100 / 100
320 ms25540 KiB
#include <bits/stdc++.h>

using namespace std;

#define endl '\n'
#define ll long long
#define all(x) (x).begin(), (x).end()

const int mxn = 3e5 + 10;

vector<int> g[mxn];
vector<pair<int, int>> edg;

int n, a, b;

int dist[mxn], from[mxn];

void dfs(int cur, int to) {
    for (int i = 0; i < mxn; i++) dist[i] = 1e6;
    dist[cur] = 0;
    queue<int> q;
    q.push(cur);
    while (q.size()) {
        int fr = q.front();
        q.pop();
        for (auto x : g[fr]) {
            if (dist[fr] + 1 < dist[x]) {
                dist[x] = dist[fr] + 1;
                from[x] = fr;
                q.push(x);
            }
        }
    }
    while (to != cur) {
        edg.push_back({from[to], to});
        to = from[to];
    }
    reverse(all(edg));
}

pair<int, int> disable = {-1, -1};

int solve(int cur, int par = -1) {
    vector<int> times;
    for (auto x : g[cur]) {
        if (x == par || make_pair(cur, x) == disable || make_pair(x, cur) == disable) continue;
        times.push_back(solve(x, cur));
    }
    int time = 0;
    sort(all(times));
    reverse(all(times));
    int cnt = 0;
    for (auto x : times) {
        time = max(time, x + cnt);
        cnt++;
    }
    return time + (par != -1);
}

bool check(int edge) {
    disable = edg[edge];
    int costA = solve(a), costB = solve(b);
    return costA <= costB;
}

int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cin >> n >> a >> b;
    for (int i = 0; i < n - 1; i++) {
        int f, t;
        cin >> f >> t;
        g[f].push_back(t);
        g[t].push_back(f);
    }
    dfs(a, b);
    int l = 0, r = edg.size();
    while (l + 1 < r) {
        int mid = (l + r) / 2;
        if (check(mid)) l = mid;
        else r = mid;
    }
    int ans = 1e9;
    disable = edg[l];
    ans = min(ans, max(solve(a), solve(b)));
    if (l + 1 < edg.size()) {
        disable = edg[l + 1];
        ans = min(ans, max(solve(a), solve(b)));
    }
    cout << ans << endl;
}
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