제출 #1214332

#제출 시각아이디문제언어결과실행 시간메모리
1214332omsincoconut던전 (IOI21_dungeons)C++17
50 / 100
7093 ms489644 KiB
/* Observation 1: After the first consecutive losses, you will lose at no more than O(log(s)) positions. */ #include "dungeons.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; int n; vector<int> s, p, w, l; const int MAXBIT = 30, MAXN = 4e5+5; int winskip[MAXBIT][MAXN], loseskip[MAXBIT][MAXN]; ll winval[MAXBIT][MAXN], loseval[MAXBIT][MAXN], wingain[MAXBIT][MAXN], losegain[MAXBIT][MAXN]; void init(int _n, vector<int> _s, vector<int> _p, vector<int> _w, vector<int> _l) { n = _n; s = _s; p = _p; w = _w; l = _l; s.push_back(0); p.push_back(0); w.push_back(n); l.push_back(n); for (int i = 0; i <= n; i++) { winskip[0][i] = w[i]; winval[0][i] = s[i]; wingain[0][i] = s[i]; loseskip[0][i] = l[i]; loseval[0][i] = s[i]; losegain[0][i] = p[i]; } for (int j = 0; j < MAXBIT-1; j++) { for (int i = 0; i <= n; i++) { int skw = winskip[j][i]; winskip[j+1][i] = winskip[j][skw]; winval[j+1][i] = max(winval[j][i], winval[j][skw] - wingain[j][i]); wingain[j+1][i] = wingain[j][i] + wingain[j][skw]; int skl = loseskip[j][i]; loseskip[j+1][i] = loseskip[j][skl]; loseval[j+1][i] = min(loseval[j][i], loseval[j][skl] - losegain[j][i]); losegain[j+1][i] = losegain[j][i] + losegain[j][skl]; } } } long long simulate(int x, int _z) { ll z = _z; // Initial losing for (int j = MAXBIT-1; j >= 0; j--) { if (loseval[j][x] > z && loseskip[j][x] != n) { z += losegain[j][x]; x = loseskip[j][x]; } } if (z >= s[x] && w[x] == n) return z+s[x]; if (z < s[x] && l[x] == n) return z+p[x]; // Winning steps while (true) { if (z >= s[x] && w[x] == n) return z+s[x]; if (z < s[x] && l[x] == n) return z+p[x]; int targ; ll val; bool islose; if (z < s[x]) { targ = l[x]; val = z + p[x]; islose = true; } else { targ = w[x]; val = z + s[x]; islose = false; } for (int j = MAXBIT-1; j >= 0; j--) { if (winval[j][targ] <= val && winskip[j][targ] != n) { val += wingain[j][targ]; targ = winskip[j][targ]; } } if (val >= s[targ] && w[targ] == n) return val+s[targ]; if (val < s[targ] && l[targ] == n) return val+p[targ]; if (targ == x && islose) { ll gain = val - z; ll iter = (s[x]-z+gain-1)/gain; z += gain*(iter-1); } else { x = targ; z = val; } } }
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