Submission #1212837

#	Time	Username	Problem	Language	Result	Execution time	Memory
1212837		Aviansh	Soccer Stadium (IOI23_soccer)	C++20	0 / 100	4610 ms	391856 KiB

soccer

#include "soccer.h"
#include <bits/stdc++.h>

using namespace std;

int biggest_stadium(int n, vector<vector<int>> F)
{
    int dp[n][n][n][n];
    for(int i = 0;i<n;i++){
        for(int j = 0;j<n;j++){
            for(int k = 0;k<n;k++){
                fill(dp[i][j][k],dp[i][j][k]+n,-1e8);
            }
        }
    }
    //{start point,endpoint,l in curr row, r in curr row.
    for(int s = 0;s<n;s++){
        //start point s.
        for(int e = s;e<n;e++){
            //end point e
            if(s==e){
                //base case.
                for(int l = 0;l<n;l++){
                    for(int r = l;r<n;r++){
                        if(F[s][r]){
                            break;
                        }
                        dp[s][e][l][r]=r-l+1;
                    }
                }
                continue;
            }
            for(int l = 0;l<n;l++){
                for(int r = l;r<n;r++){
                    if(F[e][r])
                        break;
                    for(int pl = l;pl<=r;pl++){
                        for(int pr = pl;pr<=r;pr++){
                            dp[s][e][l][r]=max(dp[s][e][l][r],dp[s][e-1][pl][pr]+(r-l+1));
                        }
                    }
                }
            }
        }
        //now end point above s, ie reverse.

        for(int e = s-1;e>=0;e--){
            //end point e
            for(int l = 0;l<n;l++){
                for(int r = l;r<n;r++){
                    if(F[e][r])
                        break;
                    for(int pl = l;pl<=r;pl++){
                        for(int pr = pl;pr<=r;pr++){
                            dp[s][e][l][r]=max(dp[s][e][l][r],dp[s][e+1][pl][pr]+(r-l+1));
                        }
                    }
                }
            }
        }
    }
    int ans = 0;
    for(int s = 0;s<n;s++){
        for(int e = s;e<n;e++){
            for(int i = s;i<=e;i++){
                for(int l = 0;l<n;l++){
                    for(int r = l;r<n;r++){
                        ans=max(ans,dp[s][i][l][r]+dp[e][i][l][r]-(r-l+1));
                    }
                }
            }
        }
    }
    return ans;
}

• Subtask 0: 0 / 0
• Subtask 1: 0 / 6
• Subtask 2: 0 / 8
• Subtask 3: 0 / 22
• Subtask 4: 0 / 18
• Subtask 5: 0 / 16
• Subtask 6: 0 / 30