Submission #1212007

#	Time	Username	Problem	Language	Result	Execution time	Memory
1212007		al95ireyiz	Topical (NOI23_topical)	C++20	100 / 100	483 ms	133664 KiB

Main

//*** Bismillah ***//
#pragma GCC optimize("O3", "fast-math", "unroll-loops", "no-stack-protector")
#include <bits/stdc++.h>
using namespace std;
#if !defined(ONLINE_JUDGE) and !defined(EVAL)
#include "template/debug.h"
#else
#define d(x...)
#endif
#define fr first
#define er erase
#define sc second
#define in insert
#define ll long long
#define pb push_back
#define vll vector<ll>
#define pll pair<ll,ll>
#define ull unsigned ll
#define vpll vector<pll>
#define len(x) (ll) x.size()
#define all(x) x.begin(),x.end()
const ll INF = 1e9;
const ll INFL = 1e18;
const ll MOD = 1e9+7;
// const ll MOD = 998244353;
const ll maxn = 1e6+5;
ll n,m,k=0;
ll p[maxn];
void _(ll tt) {
    cin >> n >> m;
    vector<vll> v(n + 1, vll(m + 1)), s(n + 1, vll(m + 1));
    vll nw(m + 1);
    vector<priority_queue<pll, vpll, greater<pll>>>q(m + 1);
    for(ll i = 1; i <= n; i ++){
        for(ll j = 1; j <= m; j ++){
            cin >> v[i][j];
            q[j].push({v[i][j], i});
        }
    }
    for(ll i = 1; i <= n; i ++){
        for(ll j = 1; j <= m; j ++){
            cin >> s[i][j];
        }
    }
    ll cv = 0, f = 1;
    while(f){
        f = 0;
        for(ll i = 1; i <= m; i ++){
            while(!q[i].empty()){
                auto [x, ind] = q[i].top();
                if(nw[i] >= x){
                    p[ind] ++;
                    if(p[ind] == m){
                        f = 1;
                        for(ll j = 1; j <= m; j ++) nw[j] += s[ind][j];
                        cv ++;
                    }
                    q[i].pop();
                }
                else break;
            }
        }
    }
    cout << cv << '\n';
}
signed main() {
    ll tm = clock();
    cin.tie(0)->sync_with_stdio(0);
    ll t = 1;
    // cin >> t;
    for(ll tt = 1; tt <= t; tt ++) {
        _(tt);
    }
    cerr << "\n\033[1;31mTime: \033[1;30m" \
         << (double)(clock()-tm)/1000000 << "\033[1;32m seconds\n";
}

• Subtask 1: 12 / 12
• Subtask 2: 28 / 28
• Subtask 3: 21 / 21
• Subtask 4: 39 / 39