Submission #1210944

#	Time	Username	Problem	Language	Result	Execution time	Memory
1210944		nerrrmin	Catfish Farm (IOI22_fish)	C++20	9 / 100	68 ms	16452 KiB

fish

#include "fish.h"
#include<bits/stdc++.h>
#define pb push_back
#include <vector>
using namespace std;
const int maxn = 305;
int n, m;
vector < pair < int, int > > g[200000];
int dp[maxn][maxn];
int pref[maxn][maxn], a[maxn][maxn];
int get(int col, int l, int r)
{
    if(r < l)return 0;
    if(col > n)return 0;
    int val = pref[col][r];
    if(l)val -= pref[col][l-1];
    return val;
}
long long p[4][200000];
long long get_p(long long col, long long l, long long r)
{
    if(r < l)return 0;
    if(col > n)return 0;
    long long val = p[col][r];
    if(l)val -= p[col][l-1];
    return val;
}
long long val[200000], d[200000][2];
long long max_weights(int N, int M, std::vector<int> X, std::vector<int> Y,
                      std::vector<int> W) {
    n = N;
    m = M;
    long long sum = 0, group1 = 1, group2 = 1, group3 = 1;
    for (int i = 0; i < m; ++ i)
    {
        if(X[i] % 2 == 1)group1 = 0;
        if(X[i] > 1)group2 = 0;
        if(Y[i] > 0)group3 = 0;
        X[i] ++;
        Y[i] ++;
        g[X[i]].pb(make_pair(Y[i], W[i]));
        sum += W[i];
        if(n <= 300)a[X[i]][Y[i]] = W[i];
        if(X[i] <= 2)p[X[i]][Y[i]] += W[i];
        if(Y[i] == 0)val[X[i]] += W[i];
    }
    if(group1)return sum;
    if(group2)
    {

        long long sum1 = 0, sum2 = 0;
        for (auto &[y, w]: g[1])
            sum1 += w;
        for (auto &[y, w]: g[2])
            sum2 += w;
            long long ans = max(sum1, sum2);
        if(n > 2)
        {
            for (int i = 1; i <= 2; ++ i)
            {
                for (int j = 1; j <= n; ++ j)
                    p[i][j] += p[i][j-1];
            }
            for (int i = 0; i <= n; ++ i)
            {
                long long curr = get_p(1, 1, i) + get_p(2, i+1, n);
                ans = max(ans, curr);
            }
        }
        return ans;
    }
    if(group3)
    {
        d[1][0] = 0;
        d[1][1] = 0;
        for (int i = 2; i <= n; ++ i)
        {
            d[i][0] = max(d[i-1][0], d[i-1][1] + val[i]);
            d[i][1] = max(d[i-1][1], d[i-1][0] + val[i-1]);
        }
        return max(d[n][0], d[n][1]);
    }
    pref[1][0] = a[1][0];
    for (int j = 1; j <= n; ++ j)
        pref[1][j] = pref[1][j-1] + a[0][j];
    dp[1][0] = 0;
    for (int j = 0; j <= n; ++ j)
    {
        dp[1][j] = get(1, 1, j);
    }
    for (int i = 2; i <= n; ++ i)
    {
        for (int j = 0; j <= n; ++ j)
        {
            for (int pre = 0; pre <= n; ++ pre)
            {
                long long curr = 0;
                if(pre <= j)
                {

                }
            }
        }
    }
  return 0;
}

• Subtask 1: 3 / 3
• Subtask 2: 6 / 6
• Subtask 3: 0 / 9
• Subtask 4: 0 / 14
• Subtask 5: 0 / 21
• Subtask 6: 0 / 17
• Subtask 7: 0 / 14
• Subtask 8: 0 / 16