Submission #1200034

#TimeUsernameProblemLanguageResultExecution timeMemory
1200034countlessSequence (APIO23_sequence)C++20
0 / 100
2107 ms589004 KiB
#include "sequence.h" #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; const ll MOD = 998244353; const ll INF = 1e18; const ld EPS = 1e-12; #define endl "\n" #define sp <<" "<< #define REP(i, a, b) for(ll i = a; i < b; i++) #define dbg(x) cout << #x << " = " << x << endl #define mp make_pair #define pb push_back #define fi first #define se second #define fast_io() ios_base::sync_with_stdio(false); cin.tie(NULL) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() struct custom_hash { static uint64_t splitmix64(uint64_t x) { // http://xorshift.di.unimi.it/splitmix64.c x += 0x9e3779b97f4a7c15; x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9; x = (x ^ (x >> 27)) * 0x94d049bb133111eb; return x ^ (x >> 31); } size_t operator()(uint64_t x) const { static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count(); return splitmix64(x + FIXED_RANDOM); } }; template <typename Key, typename Value> using hash_map = unordered_map<Key, Value, custom_hash>; mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); // uniform_int_distribution<int>(a, b)(rng); // shuffle(all(a), rng); int sequence(int N, vector<int> A) { hash_map<int, vector<int>> pos; hash_map<int, vector<int>> pref, cnt; REP(i, 0, N) pos[--A[i]].push_back(i); for (auto &x : pos) { pref[x.first].resize(N); cnt[x.first].resize(N); REP(i, 0, N) { if (A[i] < x.first) { pref[x.first][i] = 1; } else if (A[i] > x.first) { pref[x.first][i] = -1; } else { pref[x.first][i] = 0; cnt[x.first][i] = 1; } } REP(i, 1, N) { pref[x.first][i] += pref[x.first][i-1]; cnt[x.first][i] += cnt[x.first][i-1]; } } int ans = 0; REP(i, 0, N) { REP(j, 0, N) { if (A[i] != A[j]) continue; int sz = j - i + 1; int ele = A[i]; int have = cnt[ele][j] - (i > 0 ? cnt[ele][i-1] : 0); int block = pref[ele][j] - (i > 0 ? pref[ele][i-1] : 0); block = abs(block); // cerr << ele sp have sp block sp (have + block) / 2 << endl; if (have >= (have + block + 1) / 2) { ans = max(ans, have); } } } return ans; }
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