Submission #119966

#	Time	Username	Problem	Language	Result	Execution time	Memory
119966		raghav0307	Cloud Computing (CEOI18_clo)	C++14	36 / 100	425 ms	253028 KiB

clo

/*raghav0307 - Raghav Gupta*/

#include <bits/stdc++.h>
using namespace std;

#define ff first
#define ss second
#define pb push_back
#define fast_io() ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);

typedef long long ll;
typedef pair<int, int> pii;
typedef long double ld;
#define int ll

struct Item{
	int c, f, v, prod;
	Item (int cc, int ff, int vv, int type) : 
			c(cc), f(ff), v(vv), prod(type) {}
};

bool custom(Item a, Item b){
	if(a.f < b.f)
		return false;
	if(a.f > b.f)
		return true;
	if(a.prod == 1)
		return true;
	return false;
}

vector<Item> v;

const int MAXN = 2e3 + 5;
const int MAXC = 50;

int memo[2*MAXN][2*MAXN];

int dp(int pos, int left){
	if(pos == v.size())	return 0;
	if(memo[pos][left] != -1)	return memo[pos][left];
	if(v[pos].prod == 1){
		return memo[pos][left] = max( dp(pos+1, left + v[pos].c) - v[pos].v, dp(pos+1, left)); 
	}
	else if(v[pos].prod == 2){
		if(v[pos].c <= left) return memo[pos][left] =  max(dp(pos + 1, left - v[pos].c) + v[pos].v, dp(pos +1 , left));
		return memo[pos][left] = dp(pos + 1, left);
	}
}

signed main(){
	fast_io();
	memset(memo, -1, sizeof(memo));
	int n;	cin >> n;
	for(int i = 0; i < n; i++){
		int c, f, vv;
		cin >> c >> f >> vv;
		v.push_back(Item(c, f, vv, 1));
	}
	int m;	cin >> m;
	for(int i = 0; i < m; i++){
		int c, f, vv;
		cin >> c >> f >> vv;
		v.push_back(Item(c, f, vv, 2));
	}
	sort(v.begin(), v.end(), custom);
	// for(auto x : v){
	// 	cout << x.c << " " << x.f << " " << x.v << " " << x.prod << "\n";
	// }
	cout << max(dp(0, 0), 0ll) << "\n";
	return 0;
}

Compilation message (stderr)

clo.cpp: In function 'll dp(ll, ll)':
clo.cpp:40:9: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
  if(pos == v.size()) return 0;
     ~~~~^~~~~~~~~~~
clo.cpp:49:1: warning: control reaches end of non-void function [-Wreturn-type]
 }
 ^

• Subtask 1: 18 / 18
• Subtask 2: 0 / 18
• Subtask 3: 18 / 18
• Subtask 4: 0 / 18
• Subtask 5: 0 / 18
• Subtask 6: 0 / 10