제출 #1197931

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1197931		APROHACK	Robot (JOI21_ho_t4)	C++17	34 / 100	3098 ms	58624 KiB

Main

#include<bits/stdc++.h>

using namespace std;

typedef long long ll;
typedef long double ld;

//data structures

typedef pair<ll, ll> ii;
typedef vector<ii> vii;
typedef vector<ll> vll;
typedef vector<ld> vld;
typedef pair<long long, long long> pll;
typedef pair<char, ll> ci;
typedef pair<string, ll> si;
typedef vector<ll> vi;
typedef vector<string> vs;
typedef vector<vector<ll>> vvi;
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define sz(a) ((ll)a.size())
#define fi first
#define se second
#define whole(v) v.begin(), v.end()
#define rwhole(v) v.rbegin(), v.rend()
#define fro front
#define pqueue priority_queue

//answers

#define ipsb cout << -1 << endl

const ll inf = ll(1e18);

// read arr vec matr etc

#define fill(x, y) memset(x, y, sizeof(x))

// Solution

const int N = 100005, M = 200005;
ll dp[M][2]; //edge idx, color matters y/n
vector<vector<int>> ed(N);
vector<vector<int>> edges;

struct cmp{
    bool operator()(vi &a, vi &b){
        return a[0] > b[0];
    }
};

void tc(){
    int n, m; cin >> n >> m;
	edges.clear();
	for(int i = 0 ; i <= n ; ++ i)ed[i].clear();
    for(int i = 0; i < m; ++i){
        dp[i][0] = inf; dp[i][1] = inf;
        int u, v, col, cost; cin >> u >> v >> col >> cost;
        u--;
        v--;
        edges.pb({u, v, col, cost});
        ed[u].pb(i);
        ed[v].pb(i);
    }
    vector<map<int, ll>> x(n);
    for(int i = 0; i < n; ++i){
        for(auto e:ed[i]){
            x[i][edges[e][2]] += edges[e][3];
        }
    }
    pqueue<vi, vvi, cmp> pq;
    for(auto e:ed[0]){
        ll totcost = x[0][edges[e][2]];
        totcost -= edges[e][3];
        int othernode = 1;
        if(edges[e][0] != 0){
            othernode = 0;
        }
        pq.push({edges[e][3], e, othernode, 0});
        pq.push({totcost, e, othernode, 1});
        dp[e][0] = edges[e][3];
        dp[e][1] = totcost;
    }
    while(sz(pq)){
        vi state = pq.top();
        pq.pop();
        int idx = state[1];
        ll cost = state[0];
        int no = edges[idx][state[2]];
        bool fat = state[3];
        if(dp[idx][fat] != cost)continue;
        for(auto e:ed[no]){
            if(e == idx)continue;
            bool me = 0;
            if(edges[e][0] == no){
                me = 1;
            }
            ll totcost = x[no][edges[e][2]];
            totcost -= edges[e][3];
            if(fat == 0 && edges[idx][2] == edges[e][2]){
                totcost -= edges[idx][3];
            }
            if(cost + edges[e][3] < dp[e][0]){
                dp[e][0] = cost + edges[e][3];
                pq.push({cost + edges[e][3], e, me, 0});
            }
            if(cost + totcost < dp[e][1]){
                dp[e][1] = cost + totcost;
                pq.push({cost + totcost, e, me, 1});
            }
        }
    }
    ll ans = inf;
    for(auto e:ed[n-1]){
        ans = min(ans, min(dp[e][0], dp[e][1]));
    }
    if(ans == inf) ipsb;
    else cout << ans << '\n';
}

int main(){
    ios_base::sync_with_stdio(false);
    cin.tie(0); cout.tie(0);
    int t = 1;
    while(t--){
        tc();
    }
}

• Subtask 1: 34 / 34
• Subtask 2: 0 / 24
• Subtask 3: 0 / 42