Submission #1197607

#TimeUsernameProblemLanguageResultExecution timeMemory
1197607sitingfakeSkyscraper (JOI16_skyscraper)C++20
15 / 100
6 ms5192 KiB
#include<bits/stdc++.h> using namespace std; // define #define execute cerr << " Time: " << fixed << setprecision(6) << (1.0 * clock() / CLOCKS_PER_SEC) << "s\n"; #define ll long long #define int long long #define ld double #define ii pair<int,int> #define se second #define fi first #define iii pair<int,ii> #define all(v) v.begin(),v.end() #define bit(x,i) (((x)>>(i))&1LL) #define flip(x,i) ((x)^(1LL<<(i))) #define ms(d,x) memset(d,x,sizeof(d)) #define sitingfake 1 #define orz 1 //constant const ll mod = 1e9 + 7; const long long linf = 4557430888798830399; const int inf = 1061109567; const int maxarr = 1e6 + 5; const int dx[] = {0,1,-1,0}; const int dy[] = {1,0,0,-1}; template<typename T> bool maximize(T &a, const T &b) { if(a < b) {a = b; return 1;} return 0; } template<typename T> bool minimize(T &a, const T &b) { if(a > b) {a = b; return 1;} return 0; } inline void Plus(ll & a ,ll b) { b %= mod; a += b; if(a >= mod) a -= mod; if(a < 0) a += mod; return; } inline void Mul(ll & a, ll b) { a %= mod; b %= mod; a *= b; a %= mod; return; } //code const int maxn = 200; int a[maxn]; ll dp[2][105][1010][3]; int n , L; void solve(void) { cin >> n >> L; for(int i = 1; i <= n; i++) { cin >> a[i]; } sort(a + 1, a + n + 1); a[n + 1] = 10000; dp[0][0][0][0] = 1; for(int i = 1; i <= n ;i++) { int cur = i & 1; int pre = ! cur; ms(dp[cur] , 0); for(int j = 1; j <= i ; j++) { for(int k = 0 ; k <= L ; k++) { for(int m = 0 ; m <= 2 ; m++) { int diff = (2 * j - m) * (a[i+1] - a[i]); if(diff > k) continue; Plus(dp[cur][j][k][m] , dp[pre][j-1][k - diff][m]); if(m > 0) { Plus(dp[cur][j][k][m] , dp[pre][j-1][k - diff][m - 1] * (3 - m)); } Plus(dp[cur][j][k][m] , dp[pre][j][k - diff][m] * (2 * j - m)); if(m == 1) { Plus(dp[cur][j][k][m] , dp[pre][j][k - diff][m - 1] * (2 * j)); } if(m == 2) { if(i == n) { // when j = 1 note that all components merged into one when i != n we can not // we cannot append it because when we create a new one and merge it later, it //'s paradoxical Plus(dp[cur][j][k][m] , dp[pre][j][k - diff][m - 1]); } else if(j > 1) { Plus(dp[cur][j][k][m] , dp[pre][j][k - diff][m - 1] * (j - 1)); } } if(m == 2) { if(i == n)// we can only merge two end of permutation when i = n && j = 1 { Plus(dp[cur][j][k][m] , dp[pre][j + 1][k - diff][m]); } else { Plus(dp[cur][j][k][m] , dp[pre][j + 1][k - diff][m] * (j * (j - 1))); } } else if(m == 1) { Plus(dp[cur][j][k][m] , dp[pre][j + 1][k - diff][m] * j * j); } else { Plus(dp[cur][j][k][m] , dp[pre][j + 1][k - diff][m] * j * (j + 1)); } } } } } ll ans = 0; for(int i = 0; i <= L ; i++) { Plus(ans , dp[n & 1][1][i][2]); } cout << ans; } /** **/ signed main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); #define task "" if(fopen(task".inp","r")) { freopen(task".inp","r",stdin); freopen(task".out","w",stdout); } int tc; tc = 1; while(tc--) solve(); //execute; }

Compilation message (stderr)

skyscraper.cpp: In function 'int main()':
skyscraper.cpp:174:15: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  174 |        freopen(task".inp","r",stdin);
      |        ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
skyscraper.cpp:175:15: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  175 |        freopen(task".out","w",stdout);
      |        ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~
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