Submission #1197430

#	Time	Username	Problem	Language	Result	Execution time	Memory
1197430		Newtonabc	Marathon Race 2 (JOI24_ho_t3)	C++20	52 / 100	18 ms	36516 KiB

Main

#include<bits/stdc++.h>
#define int long long
using namespace std;
const int N=1e3+10;
const int M=5e5+10;
int a[M];
// time used that have kept the i left balls and j right balls recent direction is (left/right=0/1)
int dpl[N][N][2],dpr[N][N][2],qs[N];
map<int,int> mp;
signed main(){
    int n,l;
    cin>>n >>l;
    for(int i=1;i<=n;i++){
        cin>>a[i];
        mp[a[i]]++;
    }
    vector<pair<int,int>> v;
    for(auto it:mp){
        v.push_back({it.first,it.second});
    }
    int m=v.size();
    for(int i=0;i<=m;i++) for(int j=0;j<=m;j++) for(int k=0;k<2;k++) dpl[i][j][k]=dpr[i][j][k]=1e9;
    qs[0]=v[0].second;
    for(int i=1;i<m;i++) qs[i]=qs[i-1]+v[i].second;
    dpl[1][0][0]=0;
    dpr[0][1][1]=0;
    for(int i=0;i<=m;i++){
        for(int j=0;j<=m;j++){
            if(i+j>m) continue;
            int ball=qs[i-1]+qs[m-1]-qs[m-j-1];
            if(i-2>=0) dpl[i][j][0]=min(dpl[i][j][0],dpl[i-1][j][0]+((ball-v[i-1].second+1)*(v[i-1].first-v[i-2].first)));
            if(i-1>=0 && m-j<=m-1) dpl[i][j][0]=min(dpl[i][j][0],dpl[i-1][j][1]+((ball-v[i-1].second+1)*(v[m-j].first-v[i-1].first)));
            if(j-1>=0 && i-1>=0 && m-j<=m-1) dpl[i][j][1]=min(dpl[i][j][1],dpl[i][j-1][0]+((ball-v[m-j].second+1)*(v[m-j].first-v[i-1].first)));
            if(m-j+1<=m-1 && j-1>=0 && m-j<=m-1) dpl[i][j][1]=min(dpl[i][j][1],dpl[i][j-1][1]+((ball-v[m-j].second+1)*(v[m-j+1].first-v[m-j].first)));
            if(i-2>=0) dpr[i][j][0]=min(dpr[i][j][0],dpr[i-1][j][0]+((ball-v[i-1].second+1)*(v[i-1].first-v[i-2].first)));
            if(i-1>=0 && m-j<=m-1) dpr[i][j][0]=min(dpr[i][j][0],dpr[i-1][j][1]+((ball-v[i-1].second+1)*(v[m-j].first-v[i-1].first)));
            if(j-1>=0 && i-1>=0 && m-j<=m-1) dpr[i][j][1]=min(dpr[i][j][1],dpr[i][j-1][0]+((ball-v[m-j].second+1)*(v[m-j].first-v[i-1].first)));
            if(m-j+1<=m-1 && j-1>=0 && m-j<=m-1) dpr[i][j][1]=min(dpr[i][j][1],dpr[i][j-1][1]+((ball-v[m-j].second+1)*(v[m-j+1].first-v[m-j].first)));
            
        }
    }
    //cout<<dpr[0][2][0] <<"\n";
    int q;
    cin>>q;
    while(q--){
        int a,b,c;
        cin>>a >>b >>c;
        if(m>=1000){
            cout<<"No\n";
            continue;
        }
        int l=upper_bound(v.begin(),v.end(),make_pair(b,LLONG_MIN))-v.begin();
        int r=m-l;
        //cout<<l <<" " <<r <<"\n";
        int ans=INT_MAX;
        if(l!=0){
            int st=abs(a-v[0].first);
            //cout<<st <<" " <<dpl[l][m-l][0] <<" " <<(n+1LL)*(b-v[l-1].first) <<" " <<(b-v[l-1].first) <<"\n";
            ans=min(ans,st+dpl[l][m-l][0]+(n+1LL)*(b-v[l-1].first));
            if(r!=0) ans=min(ans,st+dpl[l][m-l][1]+(n+1LL)*(v[l].first-b));
        }
        if(r!=0){
            int st=abs(v[m-1].first-a);
            if(l!=0) ans=min(ans,st+dpr[l][m-l][0]+(n+1LL)*(b-v[l-1].first));
            ans=min(ans,st+dpr[l][m-l][1]+(n+1LL)*(v[l].first-b));
        }
        ans+=n;
        if(ans<=c) cout<<"Yes\n";
        else cout<<"No\n";
    }
}

• Subtask 1: 7 / 7
• Subtask 2: 7 / 7
• Subtask 3: 10 / 10
• Subtask 4: 28 / 28
• Subtask 5: 0 / 10
• Subtask 6: 0 / 19
• Subtask 7: 0 / 19