Submission #1196680

#	Time	Username	Problem	Language	Result	Execution time	Memory
1196680		iamhereforfun	Cloud Computing (CEOI18_clo)	C++20	54 / 100	158 ms	1352 KiB

clo

// IamHereForFun //

#include <bits/stdc++.h>

using namespace std;

#define LSOne(S) ((S) & -(S))

const int N = 1e5 + 5;
const int M = 45e5 + 5;
const int K = 4;
const int LG = 20;
const long long INF = -1e18;
const int MOD = 1e9 + 7;
const int B = 50;

struct Obj
{
    int c, f, v, t;
    Obj(int x, int y, int z, int a)
    {
        c = x;
        f = y;
        v = z;
        t = a;
    }
    inline bool operator<(Obj a)
    {
        if (a.f == f)
        {
            return a.t < t;
        }
        return a.f < f;
    }
    void print()
    {
        cout << c << " " << f << " " << v << " " << t << "\n";
    }
};

int n, m, num = 0;
long long dp[N];
vector<Obj> vec;

void solve()
{
    cin >> n;
    for (int x = 0; x < n; x++)
    {
        int a, b, c;
        cin >> a >> b >> c;
        vec.push_back({a, b, c, 0});
    }
    cin >> m;
    for (int x = 0; x < m; x++)
    {
        int a, b, c;
        cin >> a >> b >> c;
        vec.push_back({a, b, c, 1});
    }
    for (int x = 0; x < N; x++)
    {
        dp[x] = INF;
    }
    dp[0] = 0;
    sort(vec.begin(), vec.end());
    for (Obj o : vec)
    {
        // cout << o.c << " " << o.f << " " << o.v << " " << o.t << "\n";
        // continue;
        if (o.t == 1)
        {
            for (int x = o.c; x <= num; x++)
            {
                dp[x - o.c] = max(dp[x - o.c], dp[x] + o.v);
            }
        }
        else
        {
            for (int x = num; x >= 0; x--)
            {
                dp[x + o.c] = max(dp[x + o.c], dp[x] - o.v);
            }
            num += o.c;
        }
        // cout << num << "\n";
        // for (int x = 0; x <= num; x++)
        // {
        //     cout << dp[x] << " " << x << "\n";
        // }
    }
    cout << *max_element(dp, dp + N);
}

signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int t = 1;
    // cin >> t;
    for (int x = 1; x <= t; x++)
    {
        solve();
    }
    return 0;
}

• Subtask 1: 18 / 18
• Subtask 2: 0 / 18
• Subtask 3: 18 / 18
• Subtask 4: 0 / 18
• Subtask 5: 18 / 18
• Subtask 6: 0 / 10