Submission #1195017

#TimeUsernameProblemLanguageResultExecution timeMemory
1195017nikulid이상적인 도시 (IOI12_city)C++20
0 / 100
147 ms327680 KiB
#include <climits> #include <vector> /* lemma: I will solve subtask 2 */ using namespace std; double ans=0; vector<vector<int>> visitted, exists; // both are [y][x] vector<vector<bool>> DONE; void bfs(int I, int x, int y, int curdist){ // coords is [x,y] visitted[y][x] = I; while(ans >= 1000000000){ans -= 1000000000;} if(exists[y+1][x+1] && visitted[y+1][x+1] != I){ ans += curdist+1; ans /= 2; bfs(I, x+1, y+1, curdist+1); } if(exists[y+1][x-1] && visitted[y+1][x-1] != I){ ans += curdist+1; ans /= 2; bfs(I, x-1, y+1, curdist+1); } if(exists[y-1][x+1] && visitted[y-1][x+1] != I){ ans += curdist+1; ans /= 2; bfs(I, x+1, y-1, curdist+1); } if(exists[y-1][x-1] && visitted[y-1][x-1] != I){ ans += curdist+1; ans /= 2; bfs(I, x-1, y-1, curdist+1); } return; } int DistanceSum(int N, int *X, int *Y) { DONE = vector<vector<bool>>(N+1, vector<bool>(N+1, 0)); visitted = vector<vector<int>>(N+1, vector<int>(N+1, 0)); exists = vector<vector<int>>(N+1, vector<int>(N+1, 0)); // find min X and Y values, to translate the graph to start at (1,1) int minX=INT_MAX-1, minY=INT_MAX-1; for(int i=0; i<N; i++){ minX = min(minX, X[i]); minY = min(minY, Y[i]); } for(int i=0; i<N; i++){ exists[Y[i]-minY][X[i]-minX] = 1; } for(int i=0; i<N; i++){ bfs(i, X[i], Y[i], 0); } int realans = ans; return realans; }
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