Submission #1192439

#	Time	Username	Problem	Language	Result	Execution time	Memory
1192439		stefanopulos	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++20	100 / 100	1194 ms	63704 KiB

sortbooks

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ldb;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ldb,ldb> pdd;

#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for(auto& a : x)
 
#define sz(a) (int)(a).size()
#define fi first
#define se second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const int inf = 1e9 + 5;
const int mxN = 1000005; 

int n, q;
int niz[mxN];

vector<array<int,3>> upit[mxN];
int res[mxN];

int bor[4 * mxN];
void update(int v, int tl, int tr, int pos, int val){
    if(tl == tr){
        bor[v] = max(bor[v], val);
        return;
    }
    int mid = (tl + tr) / 2;
    if(pos <= mid)update(v * 2, tl, mid, pos, val);
    else update(v * 2 + 1, mid + 1, tr, pos, val);
    bor[v] = max(bor[v * 2], bor[v * 2 + 1]); 
}   
int kveri(int v, int tl, int tr, int l, int r){
    if(tl > r || l > tr)return 0;
    if(tl >= l && tr <= r)return bor[v];
    int mid = (tl + tr) / 2;
    return max(kveri(v * 2, tl, mid, l, r), kveri(v * 2 + 1, mid + 1, tr, l, r));
}

int main(){
    cin.tie(0)->sync_with_stdio(0);

    cin >> n >> q;
    ff(i,1,n)cin >> niz[i];

    ff(i,1,q){
        int l, r, k;
        cin >> l >> r >> k;
        upit[r].pb({l, k, i});
    }

    stack<int> stek;
    ff(i,1,n){
        while(sz(stek) && niz[stek.top()] <= niz[i]){
            stek.pop();
        }

        if(sz(stek) > 0){
            int j = stek.top(); 
            update(1,1,n,j,niz[j] + niz[i]);
        }

        stek.push(i);

        for(auto c : upit[i]){
            int l = c[0];
            int k = c[1];
            int id = c[2];
            res[id] = (kveri(1,1,n,l,i) <= k ? 1 : 0);
        }

    }

    ff(i,1,q)cout << res[i] << '\n';

    return 0;
}
/*

5 2
3 5 1 8 2
1 3 6
2 5 3

// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 8 / 8
• Subtask 2: 9 / 9
• Subtask 3: 13 / 13
• Subtask 4: 17 / 17
• Subtask 5: 30 / 30
• Subtask 6: 23 / 23