Submission #1192371

#	Time	Username	Problem	Language	Result	Execution time	Memory
1192371		wood	City Mapping (NOI18_citymapping)	C++20	13 / 100	14 ms	8392 KiB

citymapping

#include "citymapping.h"
#include <bits/stdc++.h>
using namespace std;

#define pb push_back
#define eb emplace_back
#define fi first
#define se second
typedef long long ll;
typedef pair<int, int> pint;
typedef pair<ll, ll> pll;
#define vint vector<int>
#define vpint vector<pint>
#define vll vector<ll>
#define vpll vector<pll>
#define fast_cin()                                                             \
	ios_base::sync_with_stdio(false);                                          \
	cin.tie(NULL);                                                             \
	cout.tie(NULL)
#define MOD %= 1000000007
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template <class T>
using Tree =
	tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// are you certain that you have a clear idea of your code in your head?
// don't rush to the computer it'll only make it worse, it never works
// if this is the first time reading this you definitely need to go back and
// think about the implementation

pint find_ends(int N, int Q){
	int mx = 0;
	int e1 = 0;
	int e2 = 0;
	for(int i = 1; i<N; i++){
		int k = get_distance(1,i+1);
		if(k>mx){
			mx = k;
			e1 = i;
		}
	}
	for(int i = 0; i<N; i++){
		if(i==e1) continue;
		int k = get_distance(e1+1,i+1);
		if (k>mx){
			mx = k;
			e2 = i;
		}
	}
	return make_pair(e1,e2);
}

void find_roads(int N, int Q, int A[], int B[], int W[]) {
	int n = N;
	int cur = 0;
	int mx = 0;
	pint ends = find_ends(N,Q);
	cerr<<ends.fi<<' '<<ends.se;
	pint dist[n*n]; memset(dist,0,sizeof dist);
	for(int i = 0; i<n; i++){
		if(i==ends.fi) dist[i] = make_pair(i,0);
		dist[i] = make_pair(get_distance(ends.fi+1,i+1),i);
	}
	for(int i = 0; i<n; i++) cerr<<dist[i].fi<<' '<<dist[i].se<<'\n';
	cerr<<endl;
	sort(dist,dist+n);
	for(int i = 0; i<n-1;i++){
		A[i] = dist[i].se+1;
		B[i] = dist[i+1].se+1;
		W[i] = dist[i+1].fi-dist[i].fi;

	}
	for(int i = 0; i<n-1; i++) cerr<<A[i]<<' '<<B[i]<<' '<<W[i]<<'\n';;
	cerr<<endl;
	return;
}

• Subtask 1: 0 / 9
• Subtask 2: 0 / 16
• Subtask 3: 13 / 13
• Subtask 4: 0 / 19
• Subtask 5: 0 / 43