제출 #1192282

#제출 시각아이디문제언어결과실행 시간메모리
1192282ainunnajibAlice, Bob, and Circuit (APIO23_abc)C++20
36 / 100
272 ms195976 KiB
#include <vector> #include <string> #include <map> #include <vector> #include <cmath> #include <numeric> #include <algorithm> // --- Global variables for circuit construction --- int next_gate_idx; std::vector<int>* circuit_operations; std::vector<std::vector<int>>* circuit_operands; // --- Helper function to create a new gate --- int create_gate(int op_type, int in1, int in2) { if (next_gate_idx >= circuit_operations->size()) { // Resize if needed, although the problem implies pre-allocation // based on the return value of circuit(). For safety, let's resize. // Note: Resizing might be slow; ideally, predict the size. // The maximum is 2e7 gates. Let's assume vectors grow as needed. circuit_operations->resize(next_gate_idx + 1000); // Grow in chunks circuit_operands->resize(next_gate_idx + 1000); } (*circuit_operations)[next_gate_idx] = op_type; (*circuit_operands)[next_gate_idx] = {in1, in2}; return next_gate_idx++; } // --- Basic Logic Gates --- // Reference table from PDF [cite: 25] // NOT x0: p=5 (inputs x0, x0) -> f(5, x0, x0) = NOT x0 // x0 AND x1: p=8 -> f(8, x0, x1) // x0 OR x1: p=14 -> f(14, x0, x1) // x0 XOR x1: p=6 -> f(6, x0, x1) // CONST 0: p=0 -> f(0, x0, x1) = 0 (use dummy inputs, e.g., gate 0, 0) // CONST 1: p=15 -> f(15, x0, x1) = 1 (use dummy inputs, e.g., gate 0, 0) int gate_const_0 = -1; int gate_const_1 = -1; void initialize_constants() { // Create constant gates if not already done // Need dummy inputs. Use gate 0 if la+lb > 0, otherwise handle gracefully. // Let's assume la+lb >= 1, so gate 0 exists. int dummy_input = 0; // Assuming at least one input gate exists if (gate_const_0 == -1) { gate_const_0 = create_gate(0, dummy_input, dummy_input); } if (gate_const_1 == -1) { gate_const_1 = create_gate(15, dummy_input, dummy_input); } } int create_not(int in) { return create_gate(5, in, in); // NOT x0 = f(5, x0, x0) } int create_and(int in1, int in2) { return create_gate(8, in1, in2); // AND = f(8, x0, x1) } int create_or(int in1, int in2) { return create_gate(14, in1, in2); // OR = f(14, x0, x1) } int create_xor(int in1, int in2) { return create_gate(6, in1, in2); // XOR = f(6, x0, x1) } // --- 1-bit Full Adder --- // inputs: a, b, carry_in // outputs: sum_out, carry_out struct FullAdderResult { int sum_gate; int carry_gate; }; FullAdderResult create_full_adder(int a_gate, int b_gate, int carry_in_gate) { int xor1 = create_xor(a_gate, b_gate); int sum_out = create_xor(xor1, carry_in_gate); int and1 = create_and(a_gate, b_gate); int and2 = create_and(xor1, carry_in_gate); int carry_out = create_or(and1, and2); return {sum_out, carry_out}; } // --- 16-bit Ripple Carry Adder --- // inputs: a[16], b[16], carry_in // outputs: sum[16], carry_out struct Adder16BitResult { std::vector<int> sum_gates; // 16 gates int carry_out_gate; }; Adder16BitResult create_16bit_adder(const std::vector<int>& a_gates, const std::vector<int>& b_gates, int carry_in_gate) { std::vector<int> sum_gates(16); int current_carry = carry_in_gate; for (int i = 0; i < 16; ++i) { FullAdderResult fa_res = create_full_adder(a_gates[i], b_gates[i], current_carry); sum_gates[i] = fa_res.sum_gate; current_carry = fa_res.carry_gate; } return {sum_gates, current_carry}; } // --- Multiplexer (16-bit 2-to-1) --- // sel=0 -> out=in0, sel=1 -> out=in1 // out = (in0 AND (NOT sel)) OR (in1 AND sel) std::vector<int> create_16bit_mux(int sel_gate, const std::vector<int>& in0_gates, const std::vector<int>& in1_gates) { std::vector<int> out_gates(16); int not_sel = create_not(sel_gate); for (int i = 0; i < 16; ++i) { int term0 = create_and(in0_gates[i], not_sel); int term1 = create_and(in1_gates[i], sel_gate); out_gates[i] = create_or(term0, term1); } return out_gates; } // --- Comparator (k-bit equality check) --- // returns 1 if a == b, 0 otherwise int create_k_bit_comparator(const std::vector<int>& a_gates, const std::vector<int>& b_gates) { int k = a_gates.size(); if (k == 0) return gate_const_1; // Empty vectors are equal std::vector<int> xnor_gates(k); for (int i = 0; i < k; ++i) { int xor_gate = create_xor(a_gates[i], b_gates[i]); xnor_gates[i] = create_not(xor_gate); // XNOR = NOT(XOR) } // AND all XNOR results int result_gate = xnor_gates[0]; for (int i = 1; i < k; ++i) { result_gate = create_and(result_gate, xnor_gates[i]); } return result_gate; } // --- N-to-1 16-bit Multiplexer (using tree of 2-to-1 MUXes) --- // selects one of N=inputs.size() 16-bit inputs based on select_bits // select_bits has k = ceil(log2(N)) bits std::vector<int> create_n_to_1_mux_16bit(const std::vector<int>& select_bits, const std::vector<std::vector<int>>& inputs) { int n = inputs.size(); if (n == 0) return std::vector<int>(16, gate_const_0); // Or handle error if (n == 1) return inputs[0]; std::vector<std::vector<int>> current_level_inputs = inputs; int current_select_bit_idx = 0; while (current_level_inputs.size() > 1) { std::vector<std::vector<int>> next_level_inputs; int current_size = current_level_inputs.size(); int selector_gate = select_bits[current_select_bit_idx]; for (int i = 0; i < current_size; i += 2) { if (i + 1 < current_size) { next_level_inputs.push_back(create_16bit_mux(selector_gate, current_level_inputs[i], current_level_inputs[i+1])); } else { // Odd number of inputs, pass the last one through, potentially gated by the selector? // A standard mux tree handles powers of 2. For non-powers-of-2, padding or careful handling is needed. // Let's assume N is padded to a power of 2 or handled appropriately. // Simplest: pass through if it's the last one. next_level_inputs.push_back(current_level_inputs[i]); // Proper handling might involve muxing with a zero vector if the selector is 1 for this last element. // For now, assume the structure aligns or padding handles this. } } current_level_inputs = next_level_inputs; current_select_bit_idx++; } return current_level_inputs[0]; } // --- Alice --- // Encodes member numbers into a binary string. // Assumes names map to indices 0 to n-1 based on input order. // Output: outputs_alice = [num0_bit0, ..., num0_bit15, num1_bit0, ..., num1_bit15, ...] // Return value: l_A = 16 * n int alice(const int n, const char names[][5], const unsigned short numbers[], bool outputs_alice[]) { if (n == 0) return 0; int l_A = 16 * n; for (int i = 0; i < n; ++i) { unsigned short num = numbers[i]; for (int j = 0; j < 16; ++j) { outputs_alice[i * 16 + j] = (num >> j) & 1; } } return l_A; } // --- Bob --- // Encodes the m letters (sender, recipient) into a binary string. // CRITICAL ASSUMPTION: Bob can map names to indices 0..n-1 consistently with Alice. // This usually requires Bob knowing n and the ordered list of names. // Since they aren't passed, we assume implicit context or a standard ordering (e.g., lexicographical if specified). // Let's simulate this by building the map here. In a real contest, this mapping needs clarification. // Output: outputs_bob = [sender1_idx_bits, recipient1_idx_bits, sender2_idx_bits, ...] // Return value: l_B = m * 2 * k, where k = ceil(log2(n)) // Note: If n=0 or n=1, k=1 bit needed for index. Handle n=0 case. Handle k=0 if n=1. int bob(const int m, const char senders[][5], const char recipients[][5], bool outputs_bob[]) { if (m == 0) return 0; // --- Determine n and create name-to-index map --- // This is the problematic part. We *assume* we can reconstruct the map. // Let's deduce n and the map from the unique names in senders/recipients. // Sort them to get a consistent order IF that's the implicit rule. // THIS IS A GUESS based on typical contest scenarios. std::map<std::string, int> name_to_index; std::vector<std::string> unique_names; std::map<std::string, bool> seen_names; for (int i = 0; i < m; ++i) { if (seen_names.find(senders[i]) == seen_names.end()) { unique_names.push_back(senders[i]); seen_names[senders[i]] = true; } if (seen_names.find(recipients[i]) == seen_names.end()) { unique_names.push_back(recipients[i]); seen_names[recipients[i]] = true; } } // If subtasks guarantee a specific order (e.g., a-z, aa-zz), use that. // Otherwise, sorting alphabetically is a common default. std::sort(unique_names.begin(), unique_names.end()); // If the problem guarantees all n members appear // or implies a fixed order (like subtasks 4, 7), use that info. // Without explicit info, deducing 'n' reliably is hard if some members don't interact. // Let's assume unique_names gives us the relevant members in *some* order. // The true 'n' might be larger. This needs problem clarification. // For now, proceed with the deduced list. int deduced_n = unique_names.size(); for (int i = 0; i < deduced_n; ++i) { name_to_index[unique_names[i]] = i; } // If the actual 'n' from Alice is needed, we have a problem. // Let's assume deduced_n is the effective 'n' for indexing. if (deduced_n == 0) return 0; // No members involved in letters. int k = (deduced_n <= 1) ? 1 : std::ceil(std::log2(deduced_n)); // Bits per index int l_B = m * 2 * k; int current_bit = 0; for (int i = 0; i < m; ++i) { int sender_idx = name_to_index[senders[i]]; int recipient_idx = name_to_index[recipients[i]]; // Write sender index (k bits) for (int bit_idx = 0; bit_idx < k; ++bit_idx) { outputs_bob[current_bit++] = (sender_idx >> bit_idx) & 1; } // Write recipient index (k bits) for (int bit_idx = 0; bit_idx < k; ++bit_idx) { outputs_bob[current_bit++] = (recipient_idx >> bit_idx) & 1; } } return l_B; } // --- Circuit --- // Builds the circuit to calculate the sums. int circuit(const int la, const int lb, int operations[], int operands[][2], int outputs_circuit[][16]) { if (la == 0) return la + lb; // No members, circuit is just inputs. // --- Setup --- next_gate_idx = la + lb; // Assign pointers to the output arrays // NOTE: Directly modifying input arrays like this is unusual. // Ensure this matches the expected behavior of the grader interface. std::vector<int> ops_vec(next_gate_idx); // Start with space for input gates std::vector<std::vector<int>> opnds_vec(next_gate_idx, std::vector<int>(2, -1)); circuit_operations = &ops_vec; circuit_operands = &opnds_vec; initialize_constants(); // Create CONST 0 and 1 gates int n = la / 16; int k = (n <= 1) ? 1 : std::ceil(std::log2(n)); // Bits per index int m = (k == 0 || lb == 0) ? 0 : lb / (2 * k); // Deduce m // --- Prepare Constant Index Representations --- std::vector<std::vector<int>> constant_indices(n, std::vector<int>(k)); for(int j=0; j<n; ++j) { for(int bit=0; bit<k; ++bit) { constant_indices[j][bit] = ((j >> bit) & 1) ? gate_const_1 : gate_const_0; } } // --- Prepare Constant 16-bit Zero --- std::vector<int> zero_16bit(16, gate_const_0); // --- Process Messages and Accumulate Sums --- std::vector<std::vector<int>> recipient_sums(n, zero_16bit); // Initialize sums to 0 // Iterate through each message encoded by Bob for (int msg_idx = 0; msg_idx < m; ++msg_idx) { // --- Decode Sender and Recipient Indices for this message --- std::vector<int> sender_idx_gates(k); std::vector<int> recipient_idx_gates(k); int base_bob_idx = la + msg_idx * 2 * k; for (int bit = 0; bit < k; ++bit) { sender_idx_gates[bit] = base_bob_idx + bit; recipient_idx_gates[bit] = base_bob_idx + k + bit; } // --- Select Sender's Number using N-to-1 MUX --- // Prepare inputs for the MUX: pointers to Alice's input gates for each member std::vector<std::vector<int>> sender_number_inputs(n, std::vector<int>(16)); for(int sender_id=0; sender_id < n; ++sender_id) { for(int bit=0; bit < 16; ++bit) { sender_number_inputs[sender_id][bit] = sender_id * 16 + bit; } } // This MUX is potentially huge and slow to build. // Optimization: Instead of a full MUX, directly compute the gated value for each adder. // --- Alternative: Compute Gated Number per Recipient --- // For each recipient j, calculate: N_sender_if_recipient_matches = (N_sender if R == j else 0) std::vector<int> selected_sender_number; // Placeholder // We need N_sender based on sender_idx_gates. This still requires a MUX. // Let's assume create_n_to_1_mux_16bit works, although it might be too slow/large. if (n > 0) { selected_sender_number = create_n_to_1_mux_16bit(sender_idx_gates, sender_number_inputs); } else { selected_sender_number = zero_16bit; // Handle n=0 case } // --- Add Selected Sender Number to the Correct Recipient's Sum --- for (int j = 0; j < n; ++j) { // Create comparator: is_recipient = (recipient_idx == j) ? int is_recipient_gate = create_k_bit_comparator(recipient_idx_gates, constant_indices[j]); // Gate the sender's number: gated_number = selected_sender_number AND is_recipient std::vector<int> gated_number(16); for (int bit = 0; bit < 16; ++bit) { gated_number[bit] = create_and(selected_sender_number[bit], is_recipient_gate); } // Add the gated number to the current sum for recipient j Adder16BitResult add_res = create_16bit_adder(recipient_sums[j], gated_number, gate_const_0); // carry_in = 0 recipient_sums[j] = add_res.sum_gates; // Update sum for next message // We ignore the final carry_out as it's modulo 2^16 } } // --- Final Output Assignment --- for (int j = 0; j < n; ++j) { for (int bit = 0; bit < 16; ++bit) { outputs_circuit[j][bit] = recipient_sums[j][bit]; } } // --- Copy local vectors to output arrays --- // Ensure the output arrays are large enough. // The grader expects modifications in place, but our helper functions used vectors. // Resize output arrays if necessary (risky if fixed size expected). // Copy contents. int final_gate_count = next_gate_idx; if (final_gate_count > 20000000) { // Handle error: Too many gates // Perhaps print to cerr or return a specific error code if possible // For now, just proceed, but the solution might be marked wrong. } // Directly copy results into the provided arrays. // Assume operations and operands have sufficient size allocated by the grader based on return value. for(int i=la+lb; i<final_gate_count; ++i) { if (i < ops_vec.size()) { // Basic bounds check operations[i] = ops_vec[i]; operands[i][0] = opnds_vec[i][0]; operands[i][1] = opnds_vec[i][1]; } else { // This shouldn't happen if vector growth worked correctly // Handle error or break break; } } return final_gate_count; }
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