Submission #1187477

#	Time	Username	Problem	Language	Result	Execution time	Memory
1187477		od_ali	Matching (CEOI11_mat)	C++20	0 / 100	688 ms	33372 KiB

mat

#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#define He_he_boy ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0)
#define ld long double
#define pb push_back
#define pf push_front
#define eb emplace_back

#define fi first
#define se second

#define ull unsigned long long
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define mx_e max_element
#define open freopen("fcolor.in", "r", stdin);
#define close freopen("fcolor.out", "w", stdout);
#define endl cout << '\n'
#define run(a) for (ll w23 = 1; w23 <= a; w23++)
typedef int ll;
using namespace std;

const ld eps = 0.00001, Pi = 3.14159275358979323846;
const ll mod = 1e9 + 7;
ll mod2 = 11, tt;
/// --------------------------------------------------------
ll n, m;
ll a[1000010];
ll b[1000010], p[1000010];

ll T[4000010], Sz[4000010];

void up(ll x, ll l, ll r, ll j, ll v){
	if(l > j or r < j) return;
	if(l == r){
		T[x] = v;
		Sz[x] = (v > 0);
		return;
	}
	
	ll m = (l + r) / 2;
	up(x * 2, l, m, j, v);
	up(x * 2 + 1, m + 1, r, j, v);
	
	ll k = Sz[2 * x];
	
	T[x] = T[x + x] + (p[k] * T[2 * x + 1]) % mod;T[x] %= mod;
	Sz[x] = k + Sz[2 * x + 1];
}



void Ali() {
	cin >> n >> m;
	for(ll i = 1;i <= n;i ++){
		cin >> a[i];
	}
	for(ll i = 1;i <= m;i ++){
		cin >> b[i];
	}
	ll ans = 1;
	for(ll i = 1;i < n;i ++){
		ans = (ans + p[i]) % mod;
	}
	vector<pair<ll, ll>>v;
	for(ll i = 1;i <= m;i ++){
		v.pb({b[i], i});
	}
	sort(all(v));
	for(ll i = 0 ;i < m;i ++){
		b[v[i].se] = i + 1;
	}
	ll Hs = 0;
	for(ll i = 1;i <= n;i ++){
		Hs = (Hs + (a[i] * p[i - 1]) % mod) % mod;
	}
	vector<ll>ot;
	for(ll j = 1;j <= m;j ++){
		up(1, 1, m, b[j], j);
		if(Sz[1] >= n){
			if(Sz[1] > n){
				up(1, 1, m, b[j - n], 0);
				Hs = (Hs + ans) % mod;
			}	
			if(T[1] == Hs){
				ot.pb(j - n + 1);
			}
		}
	}
	cout << ot.size() << '\n';
	for(auto to : ot){
		cout << to << ' ';
	}
	cout << '\n';
}
/// --------------------------------------------------------

int main() {
  // open
  // close;
 // He_he_boy; 
  ll gg = 1; tt = 0;p[0] = 1;
  for(ll i = 1;i <= 1e6 + 2;i ++){
  	p[i] = (p[i - 1] * mod2) % mod;
  }
//  cin >> gg;
  while (gg--) {
    Ali();
    // cout << '\n';
  }
  /*
   **PLUS ULTRA**
   */
   return 0;
}

• Subtask 1: 0 / 9
• Subtask 2: 0 / 9
• Subtask 3: 0 / 9
• Subtask 4: 0 / 9
• Subtask 5: 0 / 9
• Subtask 6: 0 / 9
• Subtask 7: 0 / 9
• Subtask 8: 0 / 9
• Subtask 9: 0 / 8
• Subtask 10: 0 / 10
• Subtask 11: 0 / 10