제출 #1187210

#제출 시각아이디문제언어결과실행 시간메모리
1187210asli_bgGap (APIO16_gap)C++20
30 / 100
2096 ms3256 KiB
#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;

#include "gap.h"

//#define int long long

typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vii;
typedef vector<bool> vb;
typedef deque<int> di;
typedef deque<pii> dii;
typedef long long ll;

typedef tree<pii,null_type,less<pii>,rb_tree_tag,
tree_order_statistics_node_update> oset;

#define fi first
#define se second
#define pb push_back
#define pf push_front

#define mid (l+r)/2
#define all(x) x.begin(),x.end()
#define FOR(i,a) for(int i=0;i<(a);i++)
#define FORE(i,a,b) for(int i=(a);i<(b);i++)

#define cont(x) for(auto el:x) cout<<el<<' ';cout<<endl;
#define contp(x) for(auto el:x) cout<<el.fi<<'-'<<el.se<<' ';cout<<endl;
#define sp <<" "<<

#define DEBUG(x) cout<<(#x) sp x<<endl
#define carp(a,b) (((a%MOD)*(b%MOD))%MOD)
#define topla(a,b) (((a%MOD)+(b%MOD))%MOD)

const ll INF=1e18;
const int MAXN=5e3+5;
const int MOD=1e9+7;


ll findGap(int t, int n){
    if(t==1){
         ll l=0;
        ll r=1e18;

        ll mn,mx;

        int ind=1;
        vector<ll> a(n+1,0);

        while(ind<=n+1-ind){
            if(l>r) break;

            MinMax(l,r,&mn,&mx);
            l=mn;
            r=mx;

            if(l==r and l==-1) break;

            a[ind]=l;
            a[n+1-ind]=r;

            l++;
            r--;
            ind++;
        }

        ll fark=0;
        FORE(i,1,n) fark=max(fark,a[i+1]-a[i]);

        return fark;
    }
    else{
        ll l=0;
        ll r=1e18;

        ll mn,mx;

        MinMax(l,r,&mn,&mx);

        vector<ll> a;

        a.pb(mn);
        a.pb(mx);

        l=mn+1;
        r=mx-1;

        int sz=(r-l+1)/(n-1);
        
        for(int i=l;i<=r;i+=sz+1){
            MinMax(i,i+sz,&mn,&mx);
            if(mn!=-1) {a.pb(mn);a.pb(mx);}
        }

        sort(all(a));

        ll fark=0;
        FORE(i,1,a.size()){
            fark=max(fark,a[i]-a[i-1]);
        }

        return fark;
    }
}
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