Submission #1187053

#	Time	Username	Problem	Language	Result	Execution time	Memory
1187053		aminjon__	Matching (CEOI11_mat)	C++17	63 / 100	349 ms	62020 KiB

mat

#include <bits/stdc++.h>
#define all(x) (x).begin(), (x).end()
#define endl '\n'
typedef unsigned int uint;
typedef  unsigned int ll;
typedef long double ld;
typedef unsigned long long ull;
using namespace std;

const ll maxn = 1e6;

const ll modd = 65537

;
const ll modd2 = 65539;

const ll p1 = 10007
;
const ll p2 = 10009;

ll P1[maxn + 1], P2[maxn + 1];

ll M;

ll f_H1(vector<ll> &A)
{
    ll res = 0;
    for (int i = 0; i < A.size(); i++)
    {
        res += (A[i]%modd * P1[i]) % modd;
        res %= modd;
    }
    return res;
}
ll f_H2(vector<ll> &A)
{
    ll res = 0;
    for (int i = 0; i < A.size(); i++)
    {
        res += (A[i]%modd2 * P2[i]) % modd2;
        res %= modd2;
    }
    return res;
}

ll h1[(1LL<<19)*3];
ll h2[(1LL<<19)*3];
ll sz[(1LL<<19)*3];
ll ans[(1LL<<19)*3];

map<ll, ll> mp;


    void update(ll need, ll val)
    {
        ll cur = M + need -  1;
        h1[cur] =(val%modd);
        h2[cur] =(val%modd2);
        sz[cur]  =  (val != 0);
        
        cur/=2;
        while(cur){
                
            h1[cur] = (h1[cur+cur] + (h1[cur+cur+1] * P1[ sz[cur+cur] ])%modd)%modd;
            h2[cur] = (h2[cur+cur] + (h2[cur+cur+1] * P2[ sz[cur+cur] ])%modd2)%modd2;
            sz[cur]=sz[cur+1+cur]+sz[cur+cur];
            cur/=2;
        }
        
        
    }
signed main()
{
    ios_base::sync_with_stdio(NULL);
    cin.tie(NULL);
    cout.tie(NULL);

    ll n, m;
    cin >> n >> m;
    vector<ll>a(n+1) , b(m+1);
    P1[0] = P2[0] = 1;
    ll add1 = 1, add2 = 1;
    for (int i = 1; i <= 1 + n; i++)
    {
        P1[i] = (P1[i - 1] * p1) % modd;
        P2[i] = (P2[i - 1] * p2) % modd2;
        if (i < n)
        {
            add1 = (add1 + P1[i]) % modd;
            add2 = (add2 + P2[i]) % modd2;
        }
    }
    M =m;
    if( (m & (m-1))){
        M = (1 << ll(log2(m)+1)  );
    }
    
    for (int i = 0; i < n; i++)
        cin >> a[i];

    for (int j = 0; j < m; j++)
    {
        cin >> b[j];
        mp[b[j]];
    }
    int ind = 0;
    for (auto &g : mp)
    {
        ind++;
        g.second = ind;
    }

    ll Hx1 = f_H1(a);
    ll Hx2 = f_H2(a);

    ll kol = 0;
    
    ll __sz = 0;
    for (int j = 0; j < m; j++)
    {
        update(mp[b[j]], j + 1);
        if (sz[1] > n)
        {
            update(mp[b[j - n]], 0);
            Hx1 = (Hx1 + add1) % modd;
            Hx2 = (Hx2 + add2) % modd2;
        }
        if (sz[1] < n)
            continue;

        if (h1[1] == Hx1 && h2[1] == Hx2)
        {
            __sz++;
            ans[__sz-1] = j-n+2;
        }
    }
    cout<<__sz<<endl;
    for(int i = 0;i < __sz;i++){
        cout<<ans[i]<<' ';
    }
    return 0;
}

• Subtask 1: 9 / 9
• Subtask 2: 9 / 9
• Subtask 3: 9 / 9
• Subtask 4: 9 / 9
• Subtask 5: 9 / 9
• Subtask 6: 9 / 9
• Subtask 7: 9 / 9
• Subtask 8: 0 / 9
• Subtask 9: 0 / 8
• Subtask 10: 0 / 10
• Subtask 11: 0 / 10