Submission #1181379

#	Time	Username	Problem	Language	Result	Execution time	Memory
1181379		TudorMa	Room Temperature (JOI24_ho_t1)	C++20	50 / 100	1 ms	328 KiB

Main

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define fi first
#define sc second
#define pb push_back
#define int long long

using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef double db;
typedef pair<int, int> pii;
template<typename type>
using ordered_set = tree<type, null_type, less<type>, rb_tree_tag, tree_order_statistics_node_update>;

const int N = 5e5 + 5, mod = 1e9 + 7, inf = 2e9;
const int dl[] = {-1, 0, 1, 0}, dc[] = {0, 1, 0, -1};
const int ddl[] = {-1, -1, -1, 0, 1, 1, 1, 0}, ddc[] = {-1, 0, 1, 1, 1, 0, -1, -1};

mt19937 gen(chrono::steady_clock::now().time_since_epoch().count());
int rng(int lo = 1, int hi = INT_MAX) {
    uniform_int_distribution<int> rnd(lo, hi);
    return rnd(gen);
}

struct mint {
    int val;
    mint(int32_t x = 0) {
        val = x % mod;
    }
    mint(long long x) {
        val = x % mod;
    }
    mint operator+(mint x) {
        return val + x.val;
    }
    mint operator-(mint x) {
        return val - x.val + mod;
    }
    mint operator*(mint x) {
        return 1LL * val * x.val;
    }
    void operator+=(mint x) {
        val = (*this + x).val;
    }
    void operator-=(mint x) {
        val = (*this - x).val;
    }
    void operator*=(mint x) {
        val = (*this * x).val;
    }
    friend auto operator>>(istream& in, mint &x) -> istream& {
        in >> x.val;
        x.val %= mod;
        return in;
    }
    friend auto operator<<(ostream& out, mint const &x) -> ostream& {
        out << x.val;
        return out;
    }
};

int n, m, a[N];

int32_t main()
{
    cin.tie(nullptr)->sync_with_stdio(0);
    
    cin >> n >> m;
    for(int i=1; i<=n; i++)
        cin >> a[i], a[i] %= m;
    
    sort(a+1, a+n+1);

    int med, ans = 0;
    for(int bulan=1; bulan<=20; bulan++) {
        if(abs(a[1] - a[n]) > abs(a[1] - a[n] + m))
            a[n] -= m;
        med = (a[1] + a[n]) / 2;
        for(int i=1; i<=n; i++)
            if(abs(a[i]-med) > abs(a[i]-m-med))
                a[i] -= m;
    }
    for(int i=1; i<=n; i++)
        ans = max(ans, abs(a[i]-med));
    
    cout << ans;
    return 0;
}

• Subtask 1: 15 / 15
• Subtask 2: 5 / 5
• Subtask 3: 30 / 30
• Subtask 4: 0 / 35
• Subtask 5: 0 / 15