#include <bits/stdc++.h>
#define rep(a,b,c) for(auto a = (b); a != (c); a++)
#define repD(a,b,c) for(auto a = (b); a != (c); a--)
#define repIn(a, b) for(auto& a : (b))
#define repIn2(a, b, c) for(auto& [a, b] : (c))
constexpr bool dbg = 1;
#define DEBUG if constexpr(dbg)
#define DC DEBUG std::cerr
#define eol std::endl
#define ll long long
#define pb push_back
using namespace std;
int main() {
ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);
int n, m;
cin >> n >> m;
vector<int> iniCol(n);
rep(i, 0, n) cin >> iniCol[i];
vector<int> ans(m + 1, 1e9);
map<pair<int, int>, int> ileTakich;
vector<int> ilePojedynczych(m + 1, 0), ilePodwojnych(m + 1, 0);
map<pair<int, int>, int> ileTakich2;
vector<int> ilePojedynczych2(m + 1, 0), ilePodwojnych2(m + 1, 0);
rep(i, 0, n - 1) {
if(i % 2 == 0) {
auto c1 = iniCol[i], c2 = iniCol[i + 1];
if(c1 == c2) ilePodwojnych[c1]++;
else ilePojedynczych[c1]++, ilePojedynczych[c2]++, ileTakich[pair{min(c1, c2), max(c1, c2)}]++;
}
else {
auto c1 = iniCol[i], c2 = iniCol[i + 1];
if(c1 == c2) ilePodwojnych2[c1]++;
else ilePojedynczych2[c1]++, ilePojedynczych2[c2]++, ileTakich2[pair{min(c1, c2), max(c1, c2)}]++;
}
}
rep(c1, 1, m + 1) rep(c2, 1, m + 1) {
int ileWsumie = n / 2;
auto ilePoj = ilePojedynczych[c1] + (c1 == c2 ? 0 : ilePojedynczych[c2] - ileTakich[pair{min(c1, c2), max(c1, c2)}]);
auto ilePod = ilePodwojnych[c1] + (c1 == c2 ? 0 : ilePodwojnych[c2]);
int ileNie = ileWsumie - ilePod - ilePoj;
auto cost1 = ileNie * 2 + ilePoj;
if(n % 2 == 1) cost1 += iniCol.back() != c1 && iniCol.back() != c2;
if(n % 2 == 0) ileWsumie--;
ilePoj = ilePojedynczych2[c1] + (c1 == c2 ? 0 : ilePojedynczych2[c2] - ileTakich2[pair{min(c1, c2), max(c1, c2)}]);
ilePod = ilePodwojnych2[c1] + (c1 == c2 ? 0 : ilePodwojnych2[c2]);
ileNie = ileWsumie - ilePod - ilePoj;
auto cost2 = ileNie * 2 + ilePoj;
cost2 += iniCol[0] != c1 && iniCol[0] != c2;
if(n % 2 == 0) cost2 += iniCol.back() != c1 && iniCol.back() != c2;
auto cost = min(cost1, cost2);
ans[c1] = min(ans[c1], cost);
ans[c2] = min(ans[c2], cost);
}
rep(i, 0, m) cout << ans[i + 1] << '\n';
}
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