# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
117908 | sebinkim | Solitaire (JOI16_solitaire) | C++14 | 2064 ms | 8336 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod = 1e9 + 7;
char A[2020], B[2020], C[2020];
ll dp[2020][6060], S[2020];
ll n, ans;
void die() { printf("0\n"); exit(0); }
int main()
{
ll i, j, k, l, x, s, s1, s2, t1, t2;
scanf("%lld%s%s%s", &n, A + 1, B + 1, C + 1);
if(A[1] == 'x' || A[n] == 'x') die();
if(C[1] == 'x' || C[n] == 'x') die();
for(i=1; i<n; i++){
if(A[i] == 'x' && A[i + 1] == 'x') die();
if(C[i] == 'x' && C[i + 1] == 'x') die();
}
dp[0][0] = 1;
for(i=1; i<=n; i++){
S[i] = S[i - 1] + (A[i] == 'x') + (B[i] == 'x') + (C[i] == 'x');
s = S[i];
if(B[i] == 'o'){
if(A[i] == 'x' && C[i] == 'x') t1 = 0;
else if(A[i] == 'x' || C[i] == 'x') t1 = 1;
else t1 = 2;
for(k=0; k<=s; k++){
if(t1 == 0) dp[i][0] = (dp[i][0] + dp[i - 1][k] * s * (s - 1)) % mod;
else if(t1 == 1) dp[i][0] = (dp[i][0] + dp[i - 1][k] * s) % mod;
else dp[i][0] = (dp[i][0] + dp[i - 1][k]) % mod;
}
if(B[i - 1] == 'o' || i < 3) continue;
s2 = S[i - 2];
if(A[i - 1] == 'x' && C[i - 1] == 'x') t2 = 0;
else if(A[i - 1] == 'x' || C[i - 1] == 'x') t2 = 1;
else t2 = 2;
for(k=0; k<=s; k++){
if(t2 == 0){
x = k * (s2 - k + 2) * (s2 - k + 1) / 2 * 2 % mod;
x = (x + (s2 - k + 3) * (s2 - k + 2) * (s2 - k + 1) / 6 * 4) % mod;
}
else if(t2 == 1) x = (s2 - k + 2) * (s2 - k + 1) / 2 % mod;
else x = 0;
x = x * dp[i - 2][k] % mod;
if(t1 == 0) dp[i][0] = (dp[i][0] + x * s * (s - 1)) % mod;
else if(t1 == 1) dp[i][0] = (dp[i][0] + x * s) % mod;
else dp[i][0] = (dp[i][0] + x) % mod;
}
}
else{
if(A[i] == 'x' && C[i] == 'x') t1 = 0;
else if(A[i] == 'x' || C[i] == 'x') t1 = 1;
else t1 = 2;
for(j=1; j<=s; j++){
for(k=0; k<=s; k++){
if(t1 == 0) dp[i][j] = (dp[i][j] + dp[i - 1][k] * (j - 1) * (j - 2)) % mod;
else if(t1 == 1) dp[i][j] = (dp[i][j] + dp[i - 1][k] * (j - 1)) % mod;
else dp[i][j] = (dp[i][j] + dp[i - 1][k]) % mod;
}
}
if(B[i - 1] == 'o' || i < 3) continue;
s2 = S[i - 2];
s1 = s2 + S[i] - S[i - 1];
if(A[i - 1] == 'x' && C[i - 1] == 'x') t2 = 0;
else if(A[i - 1] == 'x' || C[i - 1] == 'x') t2 = 1;
else t2 = 2;
for(j=1; j<=s; j++){
for(k=0; k<=s; k++){
if(t1 == 0) x = dp[i - 2][k] * (j - 1) * (j - 2) % mod;
else if(t1 == 1) x = dp[i - 2][k] * (j - 1) % mod;
else x = dp[i - 2][k];
l = max(j, k + 3 - t1);
if(t2 == 0){
dp[i][j] = (dp[i][j] + x * (s1 - l + 3) * (s1 - l + 2) * (s1 - l + 1) / 6 * 4) % mod;
if(j < l) dp[i][j] = (dp[i][j] + x * (l - j) * (s1 - l + 2) * (s1 - l + 1)) % mod;
dp[i][j + 1] = (dp[i][j + 1] + x * j * (s1 - l + 2) * (s1 - l + 1)) % mod;
}
else if(t2 == 1) dp[i][j] = (dp[i][j] + x * (s1 - l + 2) * (s1 - l + 1) / 2) % mod;
}
}
}
}
s = S[n];
for(i=0; i<=s; i++){
ans = (ans + dp[n][i]) % mod;
}
printf("%lld\n", ans);
return 0;
}
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