Submission #1175994

#	Time	Username	Problem	Language	Result	Execution time	Memory
1175994		Nonoze	Addk (eJOI21_addk)	C++20	0 / 100	111 ms	5988 KiB

Main

/*
*	Author: Nonoze
*	Created: Saturday 29/03/2025
*/
#include <bits/stdc++.h>
using namespace std;

#ifndef DEBUG
	#define dbg(...)
#endif

// #define cout cerr << "OUT: "
#define endl '\n'
#define endlfl '\n' << flush
#define quit(x) return (void)(cout << x << endl)

template<typename T> void read(T& x) { cin >> x;}
template<typename T1, typename T2> void read(pair<T1, T2>& p) { read(p.first), read(p.second);}
template<typename T> void read(vector<T>& v) { for (auto& x : v) read(x); }
template<typename T1, typename T2> void read(T1& x, T2& y) { read(x), read(y); }
template<typename T1, typename T2, typename T3> void read(T1& x, T2& y, T3& z) { read(x), read(y), read(z); }
template<typename T1, typename T2, typename T3, typename T4> void read(T1& x, T2& y, T3& z, T4& zz) { read(x), read(y), read(z), read(zz); }
template<typename T> void print(vector<T>& v) { for (auto& x : v) cout << x << ' '; cout << endl; }

#define sz(x) (int)(x.size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define make_unique(v) sort(all(v)), v.erase(unique(all(v)), (v).end())
#define pb push_back
#define mp(a, b) make_pair(a, b)
#define fi first
#define se second
#define cmin(a, b) a = min(a, b)
#define cmax(a, b) a = max(a, b)
#define YES cout << "YES" << endl
#define NO cout << "NO" << endl
#define QYES quit("YES")
#define QNO quit("NO")

#define int long long
#define double long double
const int inf = numeric_limits<int>::max() / 4;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MOD = 1e9+7, LOG=20;



void solve();

signed main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	int tt=1;
	// cin >> tt;
	while(tt--) solve();
	return 0;
}


struct segtree {
	vector<int> tl, tr, sm;
	int n;
	segtree(int _n, vector<int>& a) {
		n=_n;
		tl.resize(4*n), tr.resize(4*n), sm.resize(4*n);
		build(0, 0, n-1, a);
	}

	void build(int node, int l, int r, vector<int>& a) {
		if (l==r) {
			tl[node]=tr[node]=sm[node]=a[l];
			return;
		}
		int mid=(l+r)/2;
		build(node*2+1, l, mid, a);
		build(node*2+2, mid+1, r, a);
		sm[node]=sm[node*2+1] + sm[node*2+2];
		tl[node]=tl[node*2+1] + tl[node*2+2] + sm[node*2+2]*(mid-l+1);
		tr[node]=tr[node*2+2] + tr[node*2+1] + sm[node*2+1]*(r-mid);
	}

	void update(int node, int l, int r, int point, int val) {
		if (l>point || r<point) return;
		if (l==r) {
			tl[node]=tr[node]=sm[node]=val;
			return;
		}
		int mid=(l+r)/2;
		update(node*2+1, l, mid, point, val);
		update(node*2+2, mid+1, r, point, val);
		sm[node]=sm[node*2+1] + sm[node*2+2];
		tl[node]=tl[node*2+1] + tl[node*2+2] + sm[node*2+2]*(mid-l+1);
		tr[node]=tr[node*2+2] + tr[node*2+1] + sm[node*2+1]*(r-mid);
	}

	vector<int> query(int node, int l, int r, int ql, int qr) {
		if (l>qr || r<ql) return {-1, -1, -1};
		if (l>=ql && r<=qr) return {tl[node], tr[node], sm[node]};
		int mid=(l+r)/2;
		if (ql>mid) return query(node*2+2, mid+1, r, ql, qr);
		if (qr<=mid) return query(node*2+1, l, mid, ql, qr);
		auto left=query(node*2+1, l, mid, ql, qr);
		auto right=query(node*2+2, mid+1, r, ql, qr);
		return {
			left[0] + right[0] + right[2]*(mid-ql+1),
			right[1] + left[1] + left[2]*(qr-mid),
			left[2] + right[2]
		};
	}
};

int n, k, m, q;
vector<int> a;


void solve() {
	read(n, k);
	a.clear(), a.resize(n); read(a);
	segtree st(n, a);
	read(q);
	while (q--) {
		int t; read(t);
		if (t==1) {
			vector<int> is(k); read(is); for (auto &u: is) u--;
			vector<int> b(k); for (int i=0; i<k; i++) b[i]=a[is[i]];
			for (int i=0; i<k; i++) {
				st.update(0, 0, n-1, is[i], b[(i+1)%k]);
			}
		} else {
			int l, r; read(l, r, m); l--, r--;
			int ans=0;

			int nb=min(m-1, (r-l+1)-m+1), mul=min(m, (r-l+1)-m+1);
			if (nb) ans+=st.query(0, 0, n-1, l, l+nb-1)[0];
			if (l+nb<=r-nb) {
				ans+=st.query(0, 0, n-1, l+nb, r-nb)[2]*mul;
			}
			if (nb) ans+=st.query(0, 0, n-1, r-nb+1, r)[1];
			
			cout << ans << endl;
		}
	}
}

• Subtask 1: 0 / 36
• Subtask 2: 0 / 56
• Subtask 3: 0 / 8