Submission #1174531

#	Time	Username	Problem	Language	Result	Execution time	Memory
1174531		HappyCapybara	Shortcut (IOI16_shortcut)	C++17	31 / 100	2094 ms	440 KiB

shortcut

#include "shortcut.h"
#include<bits/stdc++.h>
using namespace std;

#define ll long long

int n;
vector<vector<ll>> st;

void update(int pos, ll val, int t, int node=1, int tl=0, int tr=n-1){
    if (tl == tr){
        st[t][node] = val;
        return;
    }
    int tm = (tl+tr)/2;
    if (pos <= tm) update(pos, val, t, node*2, tl, tm);
    else update(pos, val, t, node*2+1, tm+1, tr);
    st[t][node] = max(st[t][node*2], st[t][node*2+1]);
}

ll query(int l, int r, int t, int node=1, int tl=0, int tr=n-1){
    if (l > r) return -(1ll<<50);
    if (l <= tl && tr <= r) return st[t][node];
    int tm = (tl+tr)/2;
    ll res = -(1ll<<50);
    if (l <= tm) res = max(res, query(l, r, t, node*2, tl, tm));
    if (tm+1 <= r) res = max(res, query(l, r, t, node*2+1, tm+1, tr));
    return res;
}

ll find_shortcut(int n, vector<int> l, vector<int> d, int c){
    ::n = n;
    vector<ll> ps(n, 0);
    for (int i=0; i<n-1; i++) ps[i+1] = ps[i]+l[i];
    st.resize(2, vector<ll>(4*n, -(1ll<<50)));
    for (int i=0; i<n; i++){
        update(i, ps[i]+d[i], 0);
        update(i, ps[n-1]-ps[i]+d[i], 1);
    }
    ll bsf = (1ll<<50);
    for (int i=0; i<n; i++){
        for (int j=i+1; j<n; j++){
            ll cur = 0;
            for (int x=0; x<n-1; x++){
                int lo = x, hi = n;
                if (x >= j) lo = hi-1;
                while (lo != hi-1){
                    int m = (lo+hi)/2;
                    if (ps[m]-ps[x] > abs(ps[x]-ps[i])+abs(ps[m]-ps[j])+c) hi = m;
                    else lo = m;
                }
                //cout << i << " " << j << " " << x << " " << hi << endl;
                ll d1 = d[x]+query(x+1, hi-1, 0)-ps[x];
                ll d2 = d[x]+abs(ps[x]-ps[i])+c+query(hi, j, 1)+ps[j]-ps[n-1];
                ll d3 = d[x]+abs(ps[x]-ps[i])+c+query(max(j, hi), n-1, 0)-ps[j];
                //cout << d1 << " " << d2 << " " << d3 << endl;
                cur = max(cur, max(d1, max(d2, d3)));
            }
            //cout << i << " " << j << " " << cur << endl;
            bsf = min(bsf, cur);
        }
    }
    return bsf;
}

Compilation message (stderr)

shortcut.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~
shortcut_c.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~

• Subtask 1: 9 / 9
• Subtask 2: 14 / 14
• Subtask 3: 8 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3