Submission #1171988

#	Time	Username	Problem	Language	Result	Execution time	Memory
1171988		Hurryup_7735	Red-blue table (IZhO19_stones)	C++20	17 / 100	2096 ms	860 KiB

stones

//In The Name Of ALLAH!
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp> 

using namespace __gnu_pbds;
using namespace std;

#define ll long long
#define ld long double
#define endl '\n'
#define pb push_back
#define pf push_front
#define speedyboy ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
#define bpc __builtin_popcount
#define all(x) x.begin() , x.end()
#define allr(x) x.rbegin() , x.rend()
#define F first
#define S second
#define pll pair<ll , ll>
#define turtle tuple<ll , ll , ll>
#define pss pair<string , string>
#define YES cout << "YES" << endl;
#define NO cout << "NO" << endl;
#define ordered_set tree<ll , null_type , less<ll> , rb_tree_tag , tree_order_statistics_node_update>


const ll sz = 3e3 + 5 , INF = 1e18 ,  MOD = 998244353;
char a[sz][sz] , b[sz][sz];

ll mask , i , j , o;
void solve(){
    ll n , m;
    cin >> n >> m;
    ll mx = -1;
    for(mask = 0 ; mask < (1 << (n * m)) ; mask++){
        for(i = 0 ; i < n ; i++){
            for(j = 0 ; j < m ; j++){
                if(mask & (1 << i * m + j)) a[i][j] = '-';
                else                                   a[i][j] = '+';
            }
        }
        ll cnt = 0;
        for(i = 0 ; i < n ; i++){
            ll pos = 0 , neg = 0;
            for(j = 0 ; j < m ; j++){
                pos += (a[i][j] == '+');
                neg += (a[i][j] == '-');
            }
            if(pos > neg) cnt++;
        }
        for(j = 0 ; j < m ; j++){
            ll pos = 0 , neg = 0;
            for(i = 0 ; i < n ; i++){
                pos += (a[i][j] == '+');
                neg += (a[i][j] == '-');
            }
            if(neg > pos) cnt++;
        }
        if(mx < cnt){
            mx = cnt;
            for(i = 0 ; i < n ; i++){
                for(j = 0 ; j < m ; j++){
                    b[i][j] = a[i][j];
                }
            }
        }
    }
    cout << mx << endl;
    for(i = 0 ; i < n ; i++){
        for(j = 0 ; j < m ; j++){
            cout << b[i][j];
        }
        cout << endl;
    }
}


signed main(){
    speedyboy;
    //open;
    ll t = 1;
    cin >> t;
    while(t--){
        solve();
    }
}

• Subtask 1: 17 / 17
• Subtask 2: 0 / 10
• Subtask 3: 0 / 16
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 31