Submission #1171659

#	Time	Username	Problem	Language	Result	Execution time	Memory
1171659		aufan	Diversity (CEOI21_diversity)	C++20	64 / 100	7089 ms	3396 KiB

diversity

#include <bits/stdc++.h>
// #pragma GCC optimize("O3", "Ofast")
// #define int long long
#define ll long long
#define pb push_back
#define fi first
#define se second
#define lf (id<<1)
#define rg ((id<<1)|1)
#define md ((l+r)>>1)
#define ld long double
using namespace std;
typedef pair<int,int> pii;
typedef pair<char,char> pcc;
typedef pair<pii,int> ipii;
typedef pair<pii,pii> ipiii;
const int MAXN = 3e5+10;
const int SQRT = 600;

int n, q, a[MAXN], cnt[MAXN];
vector <ipii> que;

int l=1,r=0, dif[MAXN];
int nxl[MAXN], nxr[MAXN];
ll ans[MAXN];

signed main(){
    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
    cin>>n>>q;
    for(int i=1; i<=n; i++)
        cin>>a[i]; 
    
    for(int p=1; p<=q; p++){
        int l,r;cin>>l>>r;
        que.pb({{l,r}, p});
    }
    sort(que.begin(), que.end(), [&](auto a, auto b){
        if(a.fi.fi/SQRT != b.fi.fi/SQRT) a.fi.fi/SQRT < b.fi.fi/SQRT;
        if((a.fi.fi/SQRT) & 1) a.fi.se > b.fi.se;
        return a.fi.se < b.fi.se; 
    });

    nxl[0] = 0, nxr[0] = n+1, nxl[n+1] = 0, nxr[n+1] = n+1;
    dif[0] = MAXN;
    for(auto [xx, idx] : que){
        int le = xx.fi, ri = xx.se;
        while(le < l){
            l--; 
            dif[cnt[a[l]]]--; 

            cnt[a[l]]++; 
            dif[cnt[a[l]]]++;
            // lef(cnt[a[l]]-1, cnt[a[l]], zer, one);

            int le = cnt[a[l]]-1, ri = cnt[a[l]];
            
            int p = nxl[le], q = nxr[le];
            if(dif[cnt[a[l]]-1]==0){
                if(dif[cnt[a[l]]]==1){
                    nxl[ri] = p; nxr[ri] = q; 
                    nxr[p] = ri; nxl[q] = ri;
                } else {
                    nxr[p] = q; nxl[q] = p;
                }

                nxl[le] = 0, nxr[le] = n + 1;
            } else {
                if(dif[cnt[a[l]]]==1){ // gk pop, push
                    // cout << p<<' '<<q<<"masuk\n";
                    nxl[ri] = le; nxr[ri] = q;
                    nxr[le] = ri;
                    nxl[q] = ri; // ganti
                }
            }
        }
        while(r < ri){
            r++; 
            dif[cnt[a[r]]]--; 

            cnt[a[r]]++; 
            dif[cnt[a[r]]]++;
            // lef(cnt[a[r]]-1, cnt[a[r]], zer, one);

            int le = cnt[a[r]]-1, ri = cnt[a[r]];

            int p = nxl[le], q = nxr[le];
            if(dif[cnt[a[r]]-1]==0){
                if(dif[cnt[a[r]]]==1){
                    nxl[ri] = p; nxr[ri] = q; 
                    nxr[p] = ri; nxl[q] = ri;
                } else {
                    nxr[p] = q; nxl[q] = p;
                }

                nxl[le] = 0, nxr[le] = n + 1;
            } else {
                if(dif[cnt[a[r]]]==1){ // gk pop, push
                    // cout << p<<' '<<q<<"masuk\n";
                    nxl[ri] = le; nxr[ri] = q;
                    nxr[le] = ri;
                    nxl[q] = ri; // ganti
                }
            }
        }
        while(l < le){
            dif[cnt[a[l]]]--; 
            cnt[a[l]]--; 

            dif[cnt[a[l]]]++; 
            // rig(cnt[a[l]]+1, cnt[a[l]], zer, one);
            int le = cnt[a[l]]+1, ri = cnt[a[l]];

            int p = nxl[le], q = nxr[le];
            if(dif[cnt[a[l]]+1]==0){
                if(dif[cnt[a[l]]]==1){
                    nxl[ri] = p; nxr[ri] = q; 
                    nxr[p] = ri; nxl[q] = ri;
                } else {
                    nxr[p] = q; nxl[q] = p;
                }

                nxl[le] = 0, nxr[le] = n + 1;
            } else {
                if(dif[cnt[a[l]]]==1){ // gk pop, push
                    nxr[ri] = le; nxl[ri] = p;
                    nxl[le] = ri;
                    nxr[p] = ri; // ganti
                }
            }
            l++; 
        }
        while(ri < r){
            dif[cnt[a[r]]]--; 
            cnt[a[r]]--; 

            dif[cnt[a[r]]]++; 
            // rig(cnt[a[r]]+1, cnt[a[r]], zer, one);
            int le = cnt[a[r]]+1, ri = cnt[a[r]];
            
            int p = nxl[le], q = nxr[le];
            if(dif[cnt[a[r]]+1]==0){
                if(dif[cnt[a[r]]]==1){
                    nxl[ri] = p; nxr[ri] = q; 
                    nxr[p] = ri; nxl[q] = ri;
                } else {
                    nxr[p] = q; nxl[q] = p;
                }

                nxl[le] = 0, nxr[le] = n + 1;
            } else {
                if(dif[cnt[a[r]]]==1){ // gk pop, push
                    nxr[ri] = le; nxl[ri] = p;
                    nxl[le] = ri;
                    nxr[p] = ri; // ganti
                }
            }
            r--;  
        }

        // cout << "donemove\n";

        vector <int> vec; 
        int in = nxr[0];
        while(in!=n+1){
            // cout << in << ' ' << dif[in] << " dif\n";
            vec.pb(in); // value, len
            in = nxr[in];
        }
        reverse(vec.begin(), vec.end());

        ll res = 0, f = 0, num = 0, cur = 0, pref = 0, suf = 0;
        for(auto x : vec) {
            int c = dif[x];

            ll le = (c + (f ^ 1))>>1, ri = (c + f)>>1;

            auto calc = [&](ll y) {
                ll res = (((x * y) * (x * y + 1)) >>1) + 
                    x * x * ((y - 1) * y * (2 * (y - 1) + 1) / 6 + 
                        (((y - 1) * y / 2))>>1);
                return res;
            };

            // le to le and ri to ri
            res += calc(le);
            res += calc(ri);
            // cout << "a: " << res << '\n';

            // le to ri
            res += cur * le * x * ri * x + ((le * (le + 1)>>1) * x) * 
                (ri * x) + (le * x) * (((ri * (ri + 1))>>1) * x);
            // cout << "b: " << res << '\n';

            // le to md
            res += (le * x) * pref;
            res += (((le * (le + 1))>>1) * x) * num;
            // cout << "c: " << res << '\n';

            // md to ri
            res += suf * (ri * x);
            res += num * (((ri * (ri + 1))>>1) * x);
            // cout << "d: " << res << '\n';

            pref = (((le * (le + 1))>>1) * x) + (pref + num * le) + 
                (((ri * (ri + 1))>>1) * x + (ri * x) * (le + cur));
            suf = (((ri * (ri + 1))>>1) * x) + (suf + num * ri) + 
                (((le * (le + 1))>>1) * x + (le * x) * (ri + cur));
            
            num += c * x;
            cur += c;
            f ^= (c & 1);
        }
        ans[idx] = res;
    }
    for(int i=1; i<=q; i++) cout << ans[i] << '\n';
}

• Subtask 1: 4 / 4
• Subtask 2: 10 / 10
• Subtask 3: 8 / 8
• Subtask 4: 16 / 16
• Subtask 5: 26 / 26
• Subtask 6: 0 / 36