Submission #1171503

#	Time	Username	Problem	Language	Result	Execution time	Memory
1171503		abcsedafaef	Knapsack (NOI18_knapsack)	C++20	0 / 100	1097 ms	8256 KiB

knapsack

#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define str string
#define vi vector<int>
#define vll vector<long long>
#define vc vector<char>
#define vs vector<string>
#define pi pair<int, int>
#define vpi vector<pi>
#define vvi vector<vector<int>>
#define si set<int>
#define ins insert
#define pb(a) push_back(a)
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define rep(i, b) for (int i = 0; i < (b); i++)
#define fast_io                       \
    ios_base::sync_with_stdio(false); \
    std::cin.tie(NULL)
#define coutyes cout << "YES" << endl;
#define coutno cout << "NO" << endl;
using namespace std;

ll N = 1000000;
vll primes;
vll v(N, 1);
void sieve()
{
    v[0] = 0;
    v[1] = 0;
    ll maxN = N;
    for (int i = 2; i * i <= maxN; i++)
    {
        if (v[i] == 1)
        {
            for (int j = i * i; j <= maxN; j += i)
                v[j] = 0;
        }
    }
    for (int i = 2; i <= maxN; i++)
    {
        if (v[i] != 0)
        {
            primes.pb(i);
        }
    }
}
ll mod = 1e9 + 7;
vector<ll> fact, invFact;
ll power(ll x, ll y)
{
    ll res = 1;
    x = x % mod;
    while (y > 0)
    {
        if (y & 1)
            res = (res * x) % mod;
        y = y >> 1;
        x = (x * x) % mod;
    }
    return res;
}
void precom(int N)
{
    fact.resize(N + 1);
    invFact.resize(N + 1);
    fact[0] = 1;
    for (int i = 1; i <= N; i++)
    {
        fact[i] = (fact[i - 1] * i) % mod;
    }
    invFact[N] = power(fact[N], mod - 2);
    for (int i = N - 1; i >= 0; i--)
    {
        invFact[i] = (invFact[i + 1] * (i + 1)) % mod;
    }
}
ll ncrmod(ll n, ll r)
{
    if (r > n)
        return 0;
    return (((fact[n] * invFact[r]) % mod) * invFact[n - r]) % mod;
}
bool isPrime(ll n)
{
    if (n <= 1)
        return false;
    for (ll i = 2; i * i <= n; i++)
    {
        if (n % i == 0)
            return false;
    }
    return true;
}
void solve()
{
    int x, n;
    cin >> x >> n;
    vi v(n), w(n), t(n);
    for (int i = 0; i < n; i++)
    {
        cin >> v[i];
    }
    for (int i = 0; i < n; i++)
    {
        cin >> w[i];
    }
    for (int i = 0; i < n; i++)
    {
        cin >> t[i];
    }
    // x budget
    // n items
    // ith item has
    // v value , w cost and can be used k times
    // dp[i][j] represents max value of items we can but from i to n-1
    // when budget is j
    // skip or pick a book
    // pick ->
    // 1 -> k>0 a) dp[i][j] = dp[i+1][j-c[i]]
    //          b) dp[i][j] = dp[i+i][j]
    // 2 -> k=0 a) dp[i][j] = dp[i+1][j]
    // skip -> dp[i][j] = dp[i+1][j]
    // dp[n - 1][0] = 0;
    vector<vector<int>> dp(n + 1, vector<int>(x + 1, 0));
    for (int i = n - 1; i >= 0; i--)
    {
        for (int j = x; j >= 0; j--)
        {
            int pick = 0, skip = dp[i + 1][j];
            for (int k = 1; k <= t[i]; k++)
            {
                if (j - (k * w[i]) >= 0)
                {
                    pick = k * v[i] + dp[i + 1][j - (k * w[i])];
                    dp[i][j] = max(pick, skip);
                }
            }
        }
    }
    cout << dp[0][x];
}

int main()
{
    fast_io;
    ll t = 1;
    // cin >> t;
    while (t--)
    {
        solve();
    }
    return 0;
}

• Subtask 1: 0 / 12
• Subtask 2: 0 / 17
• Subtask 3: 0 / 20
• Subtask 4: 0 / 24
• Subtask 5: 0 / 27