Submission #1171455

#TimeUsernameProblemLanguageResultExecution timeMemory
1171455CrabCNHK blocks (IZhO14_blocks)C++20
100 / 100
150 ms3156 KiB
#include <bits/stdc++.h> #define task "BriantheCrab" #define int long long #define pii pair <int, int> #define fi first #define se second #define szf sizeof #define sz(s) (int)((s).size()) using namespace std; template <class T> void mini (T &t, T f) {if (t > f) t = f;} template <class T> void maxi (T &t, T f) {if (t < f) t = f;} const int maxN = 1e5 + 5; const int maxK = 1e2 + 5; const int inf = 1e18 + 7; const int mod = 1e9 + 7; int n, K; int a[maxN]; struct ST { int st[maxN * 4]; void upd (int id, int l, int r, int pos, int val) { if (pos < l || pos > r) { return; } if (l == r) { st[id] = val; return; } int mid = (l + r) >> 1; upd (id * 2, l, mid, pos, val); upd (id * 2 + 1, mid + 1, r, pos, val); st[id] = max (st[id * 2], st[id * 2 + 1]); } int get (int id, int l, int r, int u, int v) { if (v < l || u > r) { return 0; } if (u <= l && r <= v) { return st[id]; } int mid = (l + r) >> 1; int tL = get (id * 2, l, mid, u, v); int tR = get (id * 2 + 1, mid + 1, r, u, v); return max (tL, tR); } } T; namespace sub3 { int dp[105][105]; // minium splited with k values in current i // dp i k = max (dp j k - 1 + max (ai -> aj)) void sol () { for (int i = 1; i <= n; i ++) { cin >> a[i]; T.upd (1, 1, n, i, a[i]); } for (int i = 0; i <= n; i ++) { for (int k = 1; k <= K; k ++) { dp[i][k] = inf; } } for (int i = 1; i <= n; i ++) { dp[i][1] = T.get (1, 1, n, 1, i); } for (int i = 1; i <= n; i ++) { for (int k = 2; k <= min (i, K); k ++) { for (int j = k; j <= i; j ++) { //cout << dp[j][k - 1] << ' ' << T.get (1, 1, n, j, i) << ' ' << i << ' ' << j << ' ' << k << '\n'; mini (dp[i][k], dp[j - 1][k - 1] + T.get (1, 1, n, j, i)); } //cout << i << ' ' << k << ' ' << dp[i][k] << '\n'; } } cout << dp[n][K]; } } namespace full { int dp[2][maxN]; // min splited void sol () { for (int i = 1; i <= n; i ++) { cin >> a[i]; } for (int i = 0; i <= n; i ++) { dp[0][i] = dp[1][i] = inf; } dp[0][0] = 0; for(int j = 1; j <= K; j ++){ stack <int> st; int cur = (j & 1); int prev = 1 - cur; for (int i = 1; i <= n; i ++){ dp[cur][i] = dp[prev][i - 1] + a[i]; // stack duy tri duyet lai cac doan con ai max while(!st.empty() && a[st.top ()] <= a[i]){ mini (dp[cur][i], dp[prev][st.top ()] + a[i]); // splited to new block mini (dp[cur][i], dp[cur][st.top ()] - a[st.top ()] + a[i]); // optimize the cut on top upto i st.pop(); } if (!st.empty ()){ mini (dp[cur][i], dp[cur][st.top ()]); // not splited } st.push (i); } for (int i = 0; i <= n; i++){ dp[prev][i] = inf; } } cout << min (dp[0][n], dp[1][n]); } } void solve () { cin >> n >> K; if (n <= 1) { sub3 :: sol (); } else { full :: sol (); } } signed main () { cin.tie (nullptr) -> sync_with_stdio (false); if (fopen (task".inp", "r")) { freopen (task".inp", "r", stdin); freopen (task".out", "w", stdout); } int t = 1; //cin >> t; while (t --) { solve (); } return 0; } // thfdgb

Compilation message (stderr)

blocks.cpp: In function 'int main()':
blocks.cpp:136:17: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  136 |         freopen (task".inp", "r", stdin);
      |         ~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
blocks.cpp:137:17: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
  137 |         freopen (task".out", "w", stdout);
      |         ~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
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