제출 #1170993

#제출 시각아이디문제언어결과실행 시간메모리
1170993patgraTwo Dishes (JOI19_dishes)C++20
10 / 100
85 ms31816 KiB
#include <bits/stdc++.h> #define rep(a,b,c) for(auto a = (b); a != (c); a++) #define repD(a,b,c) for(auto a = (b); a != (c); a--) #define repIn(a, b) for(auto& a : (b)) #define repIn2(a, b, c) for(auto& [a, b] : (c)) constexpr bool dbg = 0; #define DEBUG if constexpr(dbg) #define DC DEBUG std::cerr #define eol std::endl #define ll long long #define pb push_back #define int ll using namespace std; int32_t main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); int n, m; cin >> n >> m; vector<pair<int, pair<int, int>>> a(n), b(m); rep(i, 0, n) cin >> a[i].first >> a[i].second.first >> a[i].second.second; rep(i, 0, m) cin >> b[i].first >> b[i].second.first >> b[i].second.second; bool subtask1 = true; rep(i, 1, n) if(a[i].second.first != a[i - 1].second.first) subtask1 = false; if(a.back().second.first != b[0].second.first) subtask1 = false; rep(i, 1, m) if(b[i].second.first != b[i - 1].second.first) subtask1 = false; if(subtask1) { vector<int> psB(m + 1, 0), psB2(m + 1, 0); rep(i, 0, m) psB[i + 1] = psB[i] + b[i].first; rep(i, 0, m) psB2[i + 1] = psB2[i] + b[i].second.second; int iGet = 0, myTime = 0, lastTime = a[0].second.first; int ans = -1e18; rep(i, 0, n + 1) { int where = ranges::upper_bound(psB, lastTime - myTime) - psB.begin() - 1; if(where < 0) where = 0; ans = max(ans, iGet + psB2[where]); DC << i << ' ' << where << " " << iGet << "+" << psB2[where] << eol; if(i == n) continue; myTime += a[i].first; iGet += a[i].second.second; } cout << ans << '\n'; return 0; } if(n <= 2000 && m <= 2000) { vector<ll> psA(n + 1, 0), psB(m + 1, 0); rep(i, 0, n) psA[i + 1] = psA[i] + a[i].first; rep(i, 0, m) psB[i + 1] = psB[i] + b[i].first; vector<vector<int>> dp(n + 1, vector<int>(m + 1, 0)); rep(i, 0, n + 1) rep(j, 0, m + 1) { if(j + 1 <= m) dp[i][j + 1] = max(dp[i][j + 1], dp[i][j] + (int)(psA[i] + psB[j + 1] <= b[j].second.first) * b[j].second.second); if(i + 1 <= n) dp[i + 1][j] = max(dp[i + 1][j], dp[i][j] + (int)(psA[i + 1] + psB[j] <= a[i].second.first) * a[i].second.second); } cout << dp[n][m] << '\n'; return 0; } }
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