Submission #1169032

#	Time	Username	Problem	Language	Result	Execution time	Memory
1169032		anteknne	Jelly Flavours (IOI20_jelly)	C++20	35 / 100	181 ms	190988 KiB

jelly

#include "jelly.h"
#include <bits/stdc++.h>
using namespace std;

const int MAXN = 2000;
const int MAXN2 = 200;
const int MAXX2 = 500;
const int MAXX = 10 * 1000;
int dp[MAXN2 + 1][MAXX2 + 1][MAXX2 + 1];
int dp2[MAXN + 1][MAXX + 1][2];

int find_maximum_unique(int x, int y, vector<int> a, vector<int> b) {
	int n = int(a.size());

	if (y == 0) {
        int wyn = 0;
        for (int i = 1; i <= n; i ++) {
            for (int j = 0; j <= x; j ++) {
                for (int k = 0; k <= y; k ++) {
                    dp2[i][j][k] = dp[i - 1][j][k];
                    if (j >= a[i - 1]) {
                        dp2[i][j][k] = max(dp2[i - 1][j - a[i - 1]][k] + 1, dp2[i][j][k]);
                    }
                    if (k >= b[i - 1]) {
                        dp2[i][j][k] = max(dp2[i - 1][j][k - b[i - 1]] + 1, dp2[i][j][k]);
                    }
                    wyn = max(wyn, dp2[i][j][k]);
                }
            }
        }

        return wyn;
    }

    if (n <= MAXN2 && x <= MAXX2 && y <= MAXX2) {
        int wyn = 0;
        for (int i = 1; i <= n; i ++) {
            for (int j = 0; j <= x; j ++) {
                for (int k = 0; k <= y; k ++) {
                    dp[i][j][k] = dp[i - 1][j][k];
                    if (j >= a[i - 1]) {
                        dp[i][j][k] = max(dp[i - 1][j - a[i - 1]][k] + 1, dp[i][j][k]);
                    }
                    if (k >= b[i - 1]) {
                        dp[i][j][k] = max(dp[i - 1][j][k - b[i - 1]] + 1, dp[i][j][k]);
                    }
                    wyn = max(wyn, dp[i][j][k]);
                }
            }
        }

        return wyn;
    }



	return n;
}
/*
int main () {
    cout << find_maximum_unique(7, 0, {10, 5, 2, 1, 4}, {2, 2, 2, 2, 2});
}

*/

• Subtask 1: 11 / 11
• Subtask 2: 24 / 24
• Subtask 3: 0 / 9
• Subtask 4: 0 / 10
• Subtask 5: 0 / 14
• Subtask 6: 0 / 32