Submission #1165791

#	Time	Username	Problem	Language	Result	Execution time	Memory
1165791		abcdxyz123	Fish 3 (JOI24_fish3)	C++20	100 / 100	328 ms	102724 KiB

Main

#include<bits/stdc++.h>
#define ll long long
#define pi pair<int,int>
#define fi first
#define se second
#define maxn 300005
using namespace std;
int n;
ll d;
ll a[maxn];
ll b[maxn];
ll sb[maxn];
ll dif[maxn];
ll sdif[maxn];
int pre[maxn];
int lg[maxn];
ll rmq[maxn][20];
ll get_minB(int l,int r)
{
    int k=__lg(r-l+1);
    return min(rmq[l][k],rmq[r-(1<<k)+1][k]);
}
struct
{
    int nho[4*maxn];
    ll lazy[4*maxn];
    ll s[4*maxn];
    void Push_down(int r,int lo,int hi)
    {
        int mid=(lo+hi)/2;
        if(nho[r])
        {
            nho[2*r]=1;
            lazy[2*r]=lazy[r];
            s[2*r]=lazy[r]*(mid-lo+1);

            nho[2*r+1]=1;
            lazy[2*r+1]=lazy[r];
            s[2*r+1]=lazy[r]*(hi-mid);

            nho[r]=0;
            lazy[r]=0;
        }
    }
    void update(int u,int v,ll val,int r=1,int lo=1,int hi=n)
    {
        if(u>hi||v<lo)return;
        if(u<=lo&&hi<=v)
        {
            s[r]=(hi-lo+1)*val;
            nho[r]=1;
            lazy[r]=val;
            return;
        }
        int mid=(lo+hi)/2;
        Push_down(r,lo,hi);
        update(u,v,val,2*r,lo,mid);
        update(u,v,val,2*r+1,mid+1,hi);
        s[r]=s[2*r]+s[2*r+1];
    }
    ll get(int u,int v,int r=1,int lo=1,int hi=n)
    {
        if(u>hi||v<lo)return 0;
        if(u<=lo&&hi<=v)return s[r];
        int mid=(lo+hi)/2;
        Push_down(r,lo,hi);
        return get(u,v,2*r,lo,mid)+get(u,v,2*r+1,mid+1,hi);
    }
}tree;
vector<pi>Q[maxn];
ll ans[maxn];
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
    cin>>n>>d;
    lg[1]=0;
    for(int i=2;i<=n;i++)
    {
        lg[i]=lg[i/2]+1;
    }
    for(int i=1;i<=n;i++)
    {
        cin>>a[i];
    }
    for(int i=1;i<=n;i++)
    {
        dif[i]=((a[i+1]-a[i])%d+d)%d;
        sdif[i]=sdif[i-1]+dif[i];
        b[i]=rmq[i][0]=(a[i]-sdif[i-1]);
        sb[i]=sb[i-1]+b[i];
    }
    for(int i=1;i<=n;i++)
    {
        int j=i-1;
        while(j>=1&&b[j]>=b[i])j=pre[j];
        pre[i]=j;
    }
    for(int k=1;k<=lg[n]+1;k++)
    {
        for(int i=1;i+(1<<k)-1<=n;i++)
        {
            rmq[i][k]=min(rmq[i][k-1],rmq[i+(1<<(k-1))][k-1]);
        }
    }
    int q;
    cin>>q;
    for(int i=1;i<=q;i++)
    {
        int l,r;
        cin>>l>>r;
        if(get_minB(l,r)<-(sdif[l-1]-a[l]%d))
        {
            ans[i]=-1;
            continue;
        }
        Q[r].push_back({l,i});
    }
    for(int i=1;i<=n;i++)
    {
        tree.update(pre[i]+1,i,b[i]);
        for(auto[l,id]:Q[i])
        {
            ans[id]=((sb[i]-sb[l-1])-tree.get(l,i))/d;
        }
    }



    for(int i=1;i<=q;i++)
    {
        cout<<ans[i]<<'\n';
    }
}
/*
s[i]=s[i-3]+(a[i-2]-s[i-3])%mod+(a[i-1]-a[i-2])%mod+(a[i]-a[i-1])%mod


s[i]=(a[l])%mod+(a[l+1]-a[l])%mod+...+(a[i]-a[i-1])%mod


(a[i]-sdif[i-1])+(sdif[l-1]-a[l]%d)

Voi mot thang r co dinh thi tat cac so chi cong
len mot luong co dinh
(a[i]-sdif[i-1])+(sdif[l-1]-a[l]%d)>=0
*/

• Subtask 1: 9 / 9
• Subtask 2: 7 / 7
• Subtask 3: 28 / 28
• Subtask 4: 20 / 20
• Subtask 5: 36 / 36