#include "combo.h"
#include <bits/stdc++.h>
using namespace std;
string guess_sequence(int n) {
char f = ' ';
if (press("AB")) {
if (press("A")) f = 'A';
else f = 'B';
} else {
if (press("X")) f = 'X';
else f = 'Y';
}
vector <string> str;
string cmb = "", ccmb = "ABXY";
for (char e : ccmb) if (e != f) cmb.push_back(e);
cerr << "CMB : " << cmb << '\n';
cerr << "FST : " << f << '\n';
int rt = 0, rrt = 0, l = 1;
for (int i = 0; i < 3; i++) {
str.push_back("");
str[i] += f;
}
while (l == 1) {
string p = "";
for (int i = 0; i < str.size(); i++) {
while (str[i].size() > l) str[i].pop_back();
while (str[i].size() < n) str[i] += cmb[(i+rt)%3];
p += str[i];
}
cerr << "STR : ";
for (auto e : str) cerr << e << ' ';
cerr << '\n';
rrt = rt;
if (rt == 2) {rt = (rt+1)%3, l++; break;}
int k = press(p);
if (k > l) l = k;
rt = (rt+1)%3;
}
while (l < n) {
string p = "";
for (int i = 0; i < str.size(); i++) {
while (str[i].size() > l) str[i].pop_back();
while (str[i].size() < n) str[i] += cmb[(i+rt)%3];
p += str[i];
}
cerr << "STR : ";
for (auto e : str) cerr << e << ' ';
cerr << '\n';
int k = press(p);
cerr << "K : " << k << ' ' << l << '\n';
cerr << "RT : " << rt << ' ' << rrt << '\n';
if (k > l) l = k, rrt = rt, rt = (rt+1)%3;
else {
// rrt = (rt+1)%3;
// rt = (rrt+1)%3;
rt = (rt+1)%3;
if (rt == rrt) rt = (rt+1)%3;
rrt = rt;
// for (int i = 0; i < str.size(); i++) {
// while (str[i].size() > l) str[i].pop_back();
// while (str[i].size() < l+1) str[i] += cmb[(i+rt)%3];
// }
// rt = (rt+1)%3;
// l++;
// cerr << "NEW STR : ";
// for (auto e : str) cerr << e << ' ';
// cerr << '\n';
}
}
cerr << "STR : ";
for (auto e : str) cerr << e << ' ';
cerr << '\n';
if (press(str[0]) == n) return str[0];
else if (press(str[1]) == n) return str[1];
return str[2];
}
/*
ABXXYXYXBB
ABXXBXB
[IMPORTANT] : THE FIRST LETTER APPERE ONLY ONCE
let Y be the first one
so we have X A B left
let the original string be "YBA"
we can ask 5 questions
we used 2 for finding the first one already -> 3 left
we have to get one character when we ask one time
binary searching uses 2 -> we have to change the way
we can add up to 4n long combos -> should have sth to do with it
YAA YBB YXX -> 2 -> so we know that we should cut at 2
YA YB YX
YAB YBX YXA -> if no then it will be sth in YAX YBA YXB
*/
